Created
May 5, 2017 07:24
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模拟这个题目的过程
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# 模拟这个题目的过程 | |
# https://mp.weixin.qq.com/s?__biz=MzIzMTc0NzAwMA==&mid=2247483759&idx=1&sn=933d3522dcc197b547696ad522652b8b&key=281224a0b07438ec8edb2e3a289a23f072754ac6a4b26d9e3ce3e38cca13ec9be38b36c21c8340b80c94deb264a2ff916029a398d55725d4128d04bbbef6653083d77490729372eca7851e6b4673eac2&ascene=0&uin=MTQ0OTk4MDMwMA%3D%3D&devicetype=iMac+MacBookPro11%2C1+OSX+OSX+10.12.4+build(16E195)&version=12020510&nettype=WIFI&fontScale=100&pass_ticket=1TrgoYI6A%2Fe9EM1BEXmWAwjoNDPwfCcCsU5W1LgXMf%2BV1wgkhzYikLhX8b3Ru9op | |
import numpy as np | |
import matplotlib.pyplot as plt | |
def f0(xarr, a, c, d): | |
l = [] | |
cyclelen = d + 1.0 * c / a | |
for x in xarr: | |
cycle = np.floor(x / cyclelen); | |
basey1 = c * cycle; | |
basey2 = c * cycle + c; | |
y = basey1 + (x % cyclelen) * a; | |
if y > basey2 : y = basey2; | |
l.append(y) | |
return l | |
def f1(xarr) : return f0(xarr, 120, 200, 1) | |
def f2(xarr) : return f0(xarr, 100, 200, 1) | |
x = np.arange(0, 50, 0.1); | |
plt.plot(x, f1(x), label='P1') | |
plt.plot(x, f2(x), label='P2') | |
plt.plot(x, np.subtract(f1(x), f2(x)), label='distance') | |
plt.grid(b=True, which='both', color='0.65',linestyle='-') | |
plt.legend(loc='best') | |
plt.show() |
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