Easy way to provision a lot of users in Zimbra-X. Run with -h option for help.

create-users

#!/bin/bash
prefix="test"
domain="zmc.com"
ilen=1
pw=test123

function usage {
    echo "usage: $0 -p <prefix> -d <domain> -w <password> [-z] <num-users>"
    echo "defaults:"
    echo "- prefix=$prefix"
    echo "- domain=$domain"
    echo "- password=$pw"
    echo ""
    echo "If you include -z option, will zero-pad the user index so all are the same length."
    echo "For example, if you ask for 100 users to be created, and you specify the -z option,"
    echo "then the email addresses will look like this: ${prefix}001@${domain} - ${prefix}100@${domain}."
    echo "Without the -z option they will look like this: ${prefix}1@${domain} - ${prefix}100@${domain}." 
    exit 1
}

pad_users=false
while getopts ":w:p:d:zh" opt; do
    case ${opt} in
      p )
        prefix=$OPTARG
        ;;
      d )
        domain=$OPTARG
        ;;
      z )
     	pad_users=true
        ;;
      w )
        pw=$OPTARG
        ;;
      h )
        usage
        ;;
     \? )
        echo "Invalid option: $OPTARG" 1>&2
        usage
        ;;
      : )
        echo "Invalid option: $OPTARG requires an argument" 1>&2
        usage
        ;;
    esac
done
shift $((OPTIND -1))

num_users="$1"
if [ -z "${num_users}" ]; then
    echo "must specify number of users"
    usage
fi

echo "creating $num_users users with prefix=$prefix, domain=$domain, pad_users=$pad_users, password=$pw"

if [ $pad_users == true ]; then
    ilen=$(expr length $num_users)
fi

i=1
while [ $i -le $num_users ]; do
    ii=$(printf "%0${ilen}d" $i)
    u="${prefix}$ii@${domain}"
    echo "creating user $u with password $pw"
    kubectl exec -it zmc-ldap-0 -- sudo -i -u zimbra zmprov ca "$u" "$pw"
    i=$(expr $i + 1)
done