Created
September 28, 2018 01:20
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import numpy as np | |
import itertools | |
keypad = [list(range(n, n+3)) for n in range(1, 10, 3)] | |
keypad.append([None, 0, None]) | |
keypad = np.array(keypad) | |
def get_values(obs): | |
x, y = np.where(keypad == obs) | |
x, y = x[0], y[0] | |
possibilities = [] | |
for i in [-1, 0, 1]: | |
for j in [-1, 0, 1]: | |
if i + j not in [-1, 1] or 0 > x + i < 2 or 0 > y + j < 2: | |
continue | |
try: | |
possibilities.append(keypad[x + i, y + j]) | |
except IndexError: | |
continue | |
return [n for n in possibilities if n is not None] | |
def get_pins(*obs): | |
return sorted(itertools.product(*[get_values(o) for o in obs])) | |
print(get_pins(5,2)) |
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