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// Function to return the count of maximum | |
// consecutive 1's in a binary circular array | |
public static int getMaxLength(int arr[]) { | |
int n = arr.length; | |
// Starting index | |
int start = 0; | |
//it will contain number of ones from left | |
//to right till we encounter zero. | |
int onesFromStart = 0; | |
while (start < n && arr[start] == 1) { | |
onesFromStart++; | |
start++; | |
} | |
// Ending index | |
int end = n - 1; | |
//it will contain number of ones from right | |
//to left till we encounter zero. | |
int onesFromEnd = 0; | |
while (end >= 0 && arr[end] == 1) { | |
onesFromEnd++; | |
end--; | |
} | |
// The array contains all 1s | |
if (start > end) | |
return n; | |
//number of ones between start and end | |
int onesInMid = 0; | |
int result = 0; | |
for (int i = start; i <= end; i++) { | |
if (arr[i] == 1) { | |
onesInMid++; | |
result = Math.max(result, onesInMid); | |
} else | |
onesInMid = 0; | |
} | |
return Math.max(result, onesFromStart + onesFromEnd); | |
} |
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