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gregretkowski/aptcompare.py

Created September 25, 2012 17:52
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python script to compare apt version numbers
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aptcompare.py
#!/usr/bin/python
# Usage:
# python aptcompare.py foo-2.0.873-3ubuntu1 foo-2.0.873-3ubuntu1+foo
# Outputs:
# version foo-2.0.873-3ubuntu1 < version foo-2.0.873-3ubuntu1+foo
# See:
# http://stackoverflow.com/questions/4957514/how-to-compare-debian-package-versions
import apt
import sys
a=sys.argv[1]
b=sys.argv[2]
vc=apt.VersionCompare(a,b)
if vc > 0:
print('version %s > version %s' % (a, b) )
elif vc == 0:
print('version %s == version %s' % (a, b) )
elif vc < 0:
print('version %s < version %s' % (a, b) )
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