Misc python tasks

Misc exercises_final_assessments.py

#Read in the contents of the file SP500.txt which has monthly data for 2016 and 2017 
#about the S&P 500 closing prices as well as some other financial indicators, 
#including the “Long Term Interest Rate”, which is interest rate paid on 10-year U.S. government bonds.
#Write a program that computes the average closing price (the second column, labeled SP500) 
#and the highest long-term interest rate. Both should be computed only for the period from June 2016 through May 2017. 
#Save the results in the variables mean_SP and max_interest

with open("SP500.txt", "r") as file:
    new = file.readlines()
    closing_price = []
    interest_rate = []
    for x in new[6:18]:
        y = x.split(",")
        closing_price.append(y[1])
        interest_rate.append(y[5])
   
    sum_of_numbers = 0
    for each in closing_price:
        sum_of_numbers = sum_of_numbers + float(each)
   
    mean_SP = sum_of_numbers/len(closing_price)
    print(float(mean_SP))
    max_interest = 0
    for i in interest_rate:
        if float(i) > max_interest:
            max_interest = float(i)
    print(max_interest)

#Write code that uses the string stored in org and creates an acronym which is assigned to the variable acro. 
#Only the first letter of each word should be used, each letter in the acronym should be a capital letter, 
#and there should be nothing to separate the letters of the acronym. 
#Words that should not be included in the acronym are stored in the list stopwords    
  
stopwords = ['to', 'a', 'for', 'by', 'an', 'am', 'the', 'so', 'it', 'and', "The"]
org = "The organization for health, safety, and education"
new=org.split()
acro=''
for word in new:
    if word not in stopwords:
        acro=acro + str.upper(word[0])
print(acro)
     
#Write code that uses the string stored in sent and creates an acronym which is assigned to the variable acro. 
#The first two letters of each word should be used, each letter in the acronym should be a capital letter, 
#and each element of the acronym should be separated by a “. ” (dot and space). 
#Words that should not be included in the acronym are stored in the list stopwords

stopwords = ['to', 'a', 'for', 'by', 'an', 'am', 'the', 'so', 'it', 'and', 'The']
sent = "The water earth and air are vital"
new = sent.split()
print(new)
acro = ''
for word in new:
    if word not in stopwords:
        acro = acro + str.upper(word[:2]) + "." + " "
acro = acro[0:-2]
print(acro)

#Provided is a list of data about a store’s inventory where each item in the list represents the name of an item, 
#how much is in stock, and how much it costs. Print out each item in the list with the same formatting, 
#using the .format method (not string concatenation). 
#For example, the first print statment should read The store has 12 shoes, each for 29.99 USD.

inventory = ["shoes, 12, 29.99", "shirts, 20, 9.99", 
             "sweatpants, 25, 15.00", "scarves, 13, 7.75"]
for x in inventory:
    y = x.split(",")
    instock = y[1]
    item_name = y[0]
    price = y[2]
    statement = 'The store has{} {}, each for{} USD.'.format(instock, item_name, price)
    print(statement)

#A palindrome is a phrase that, if reversed, would read the exact same. 
#Write code that checks if p_phrase is a palindrome by reversing it 
#and then checking if the reversed version is equal to the original. 
#Assign the reversed version of p_phrase to the variable r_phrase so that we can check your work.

p_phrase = "was it a car or a cat I saw"
r_phrase=''.join(reversed(p_phrase))
print(r_phrase)  

#OR

p_phrase = "was it a car or a cat I saw"
stringlength = len(p_phrase)
p_phrase[stringlength::-1]
r_phrase = p_phrase[stringlength::-1]
print(r_phrase)
    
#The string module provides sequences of various types of Python characters. 
#It has an attribute called digits that produces the string ‘0123456789’. 
#Import the module and assign this string to the variable nums. 
#Below, we have provided a list of characters called chars. 
#Using nums and chars, produce a list called is_num that consists of tuples. 
#The first element of each tuple should be the character from chars, 
#and the second element should be a Boolean that reflects whether or not it is a Python digit

import string 
chars = ['h', '1', 'C', 'i', '9', 'True', '3.1', '8', 'F', '4', 'j']
nums=string.digits
print(nums)
is_num =[]
for char in chars:
    is_num.append((char,char in nums))
print(is_num)
    
#Below are a set of scores that students have received in the past semester. 
#Write code to determine how many are 90 or above and assign that result to the value a_scores    

scores = "67 80 90 78 93 20 79 89 96 97 92 88 79 68 58 90 98 100 79 74 83 88 80 86 85 70 90 100"
new_scores = []
new = scores.split()
for x in new:
    new_scores.append(int(x))
b_scores = []
for each in new_scores:
    if each >= 90:
        b_scores.append(each)
a_scores = len(b_scores)
print(a_scores)
    
    
#Ex 10.14 #Create a list called destination using the data stored in travel_plans.txt. 
#Each element of the list should contain a line from the file that lists a country and cities inside that country. 
#Hint: each line that has this information also has a colon : in it.

file = open("travel_plans.txt", "r")
line = file.readlines()
destination = []
for words in line:
    if ":" in words:
        destination.append(words)
print (destination)


#Create a list called j_emotions that contains every word in emotion_words.txt that begins with the letter “j”.

file = open("emotion_words.txt", "r")
f = file.read()
j_emotions = []
words = f.split()
for line in words:
    if "j" in line:
        j_emotions.append(line)
        print(j_emotions)

        
#Ex 11.6 #Provided is a string saved to the variable name sentence. 
#Split the string into a list of words, then create a dictionary that contains each word and 
#the number of times it occurs. Save this dictionary to the variable name word_counts.

sentence = "The dog chased the rabbit into the forest but the rabbit was too quick."
txt = sentence.split()
word_counts = {}
for c in txt:
    if c not in word_counts:
        word_counts[c] = 0
    word_counts[c] = word_counts[c] + 1
for c in word_counts.keys():
    print(c+ " -" + str(word_counts[c]) + " times")
        
        
        
#Create a dictionary called char_d from the string stri, so that the key is a character and 
#the value is how many times it occurs.

stri = "what can i do"
char_d = {}
for x in stri:
    if x not in char_d:
        char_d[x] = 0
    char_d[x] = char_d[x] +1
    
 print(char_d[x])
 print(char_d.keys())
 print(char_d.values())


 #Create a dictionary called lett_d that keeps track of all of the characters in the string product 
 #and notes how many times each character was seen. Then, find the key with the highest value in this dictionary 
 #and assign that key to max_value.
    
product = "iphone and android phones"
lett_d = {}
for x in product:
    if x not in lett_d:
        lett_d[x]=0
    lett_d[x] = lett_d[x] + 1
list1 = list(lett_d.keys())
print(list1)
max_value = list1[0]
for key in list1:
    if lett_d[key] > lett_d[max_value]:
        max_value = key
print(max_value)


#Write a program that finds the most used 7 letter word in scarlet3.txt
f = open('scarlet3.txt', 'r')
contents = f.read()
d = {}

for w in contents.split():
    if len(w) == 7:
        if w not in d:
            d[w] = 1
        else:
            d[w] = d[w] + 1

dkeys = d.keys()
print(dkeys)
most_used = dkeys[0]
for k in dkeys:
    if d[k] > d[most_used]:
        most_used = k

print("The most used word is '" + most_used + "', which is used " + str(d[most_used])+ " times")


#Challenge For each word in words, add ‘d’ to the end of the word if the word ends in “e” to make it past tense. 
#Otherwise, add ‘ed’ to make it past tense. 
#Save these past tense words to a list called past_tense

words = ["adopt", "bake", "beam", "confide", "grill", "plant", "time", "wave", "wish"]
past_tense = []

for word in words:
    if word[len(word)-1] == 'e':
        past_tense.append(word + 'd')
    else:
        past_tense.append(word + 'ed')

print(past_tense)

#For each word in the list verbs, add an -ing ending. Save this new list in a new list, ing

verbs = ["kayak", "cry", "walk", "eat", "drink", "fly"]
ing = []
for w in verbs:
    x = w + "ing"
    ing.append(x)
print(ing)


#Challenge 
#Overwrite the list numbs so that each of the original numbers are increased by 5

numbs = [5, 10, 15, 20, 25]
for i in range(0,5):
    numbs[i] = numbs[i]+ 5
print(numbs)

#For each number in lst_nums, multiply that number by 2 and append it to a new list called larger_nums

lst_nums = [4, 29, 5.3, 10, 2, 1817, 1967, 9, 31.32]
larger_nums = []
for i in lst_nums:
    x = i*2
    larger_nums.append(x)
print(larger_nums)

#Display the image below to the right hand side where the 0 is going to be ' ', and the 1 is going to be '*'. This will reveal an image!
picture = [
  [0,0,0,1,0,0,0],
  [0,0,1,1,1,0,0],
  [0,1,1,1,1,1,0],
  [1,1,1,1,1,1,1],
  [0,0,0,1,0,0,0],
  [0,0,0,1,0,0,0]
]


for row in picture:
  for each in row:
    if (each == 1):
      print('*', end ="")
    else:
      print(' ', end ="")
  print('')
        
# Check for duplicates in list

some_list = ['a', 'b', 'c', 'b', 'd', 'm', 'n', 'n']

duplicates = []
for value in some_list:
    if some_list.count(value) > 1:
        if value not in duplicates:
            duplicates.append(value)

print(duplicates)

# Write a function to return highest even number from a list

def highest_even(li):
  max = 0
  for i in li:
    if i % 2 == 0 and i > max:
      max = i
  i = i+1
  return max

print (highest_even([10,1,2,3,4,12]))

Hi. For SP500.txt i did my own version of code.
I'm starting to learning python so if anyone want to see it then great:)

with open('SP500.txt','r') as sp_file:
    #podzielenie pliku do listy
    sp_file=sp_file.readlines()
    close_price=[]
    interest_rate=[]
    count=0
    acc_int=0
    #dla wierszy od 6 do 18 (June 2016 through May 2017)
    for x in sp_file[6:18]:
        y=x.split(',')
        close_price.append(y[1])
        interest_rate.append(y[5])
        count+=1
    for i in range(count):
        close_price[i]=float(close_price[i])
        acc_int=acc_int+close_price[i]
    mean_SP=acc_int/count
    print(mean_SP)
    for a in range(count):
        interest_rate[a]=float(interest_rate[a])
    max_interest=interest_rate[0]
    for z in range(count):
        #print("max_interest={} ; interest_rate={}".format(max_interest,interest_rate[z]))
        if interest_rate[z]>max_interest:
            max_interest=interest_rate[z]
    print(max_interest)