Showcasing float rounding with a very roundabout way of calculating square roots

sqrt_digits.py

import math
from decimal import *

# Max precision `prec` you'd want
getcontext().prec = 80

def integral_root(num):
    for i in range(int(num) + 1):
        if i ** 2 == num:
            return i
        elif i ** 2 > num:
            return i - 1

def funky_sqrt(num, prec):
    n = str(integral_root(num)) + "."
    for _ in range(prec + 1):
        for j in range(1, 10):
            test_n = Decimal(n + str(j))
            if test_n ** 2 > num:
                n += str(j - 1)
                break
        else:
            n += "9"
    return Decimal(n)

n = 10002
print("math.sqrt:", math.sqrt(n))
print("this algo:", funky_sqrt(n, 78))