Loops and arrays solutions

Loops and arrays solutions

Max and min

function max(numbers) {
  let maximum = numbers[0]
  for(i = 0; i < numbers.length; i++){
    if (numbers[i] > maximum){
      maximum = numbers[i]
    }
  } return maximum;
}

function min(numbers) {
  let minimum = numbers[0]
  for(i = 0; i < numbers.length; i++){
    if (numbers[i] < minimum){
      minimum = numbers[i]
    }
  } return minimum;
}


Average

function average(numbers) {
  let total = 0;
  for(i = 0; i < numbers.length; i++){
    total += numbers[i];
  } return total / numbers.length;
}

Fizzbuzz (There's got to be a shorter way to do this but I'm not sure what it is)

function fizzBuzz(countTo) {
  function timesNumber(num){
    if(num % 3 === 0 && num % 5 === 0){return "fizzbuzz"}
    if(num % 3 === 0){return "fizz"}
    if(num % 5 === 0){return "buzz"}
    else {return num}
  }
  let counter = 1
  let sequence = []
  while (counter < countTo + 1) {
    sequence.push(counter);
    counter ++;
  } 
  return sequence.map(timesNumber);
}