Grokking assignment: Most frequent word

Grokking assignment: Most frequent word

function getTokens(rawString) {
  //This section splits words into strings by splitting at spaces and punctuation, makes them all lowercase so upper/lowercase letters will be counted as the same, and removes all non-truthy values.
  return rawString.toLowerCase().split(/[ ,!.";:-]+/).filter(Boolean)
    //This sorts the elements alphabetically
  .sort();
}

function mostFrequentWord(text) {
  //Runs the above function getTokens and identifies the results as the variable "words"
  let words = getTokens(text);
  //Sets a running list (currently empty) of the most-used words
  let wordFrequencies = {}
  //Runs through all words in the words variable
  for (let i = 0; i <= words.length; i++) {
    //If the word has already appeared and is stored in the list as a variable, add one more to its value in the wordFrequencies list
    if (words[i] in wordFrequencies) {
      wordFrequencies[words[i]]++;
    //Otherwise, add it to the wordFrequencies list with a value of one
    } else {
      wordFrequencies[words[i]] = 1;
    }
  }

  //Identifies the first word on the list, which since a sort was run, should be the first alphabetically
  let currentMaxKey = Object.keys(wordFrequencies)[0];

  //Identifies the frequency of that word
  let currentMaxCount = wordFrequencies[currentMaxKey];

//Runs through the entire list of words. If a word's frequency is greater than the current max, that word becomes the new currentMaxKey and its value becomes the new currentMaxCount.
  for (let word in wordFrequencies) {
    if (wordFrequencies[word] > currentMaxCount) {
      currentMaxKey = word;
      currentMaxCount = wordFrequencies[word];
    }
  }
//Returns the word with the highest frequency and ends the function.
  return currentMaxKey;
}