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#101 LeetCode Symmetric Tree Iterative Javascript Solution
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var isSymmetric = function (root) { | |
if (!root) { | |
return "no tree was provided 🤔"; // return true | |
} | |
if (!root.left && !root.right) { | |
return "you have a symmetric tree that only has 1 node...the root 🌱!"; // return true | |
} | |
let queue = []; | |
queue.unshift(root); | |
queue.unshift(root); | |
let leftNode; | |
let rightNode; | |
while (queue.length) { | |
console.log({ queue }); // check queue size to calculate space complexity. In symmetric tree can be num nodes +1 | |
console.log("running this code block"); // this will run at most for the total number of nodes in the tree | |
leftNode = queue[0]; | |
queue.shift(); | |
rightNode = queue[0]; | |
queue.shift(); | |
if (leftNode.value !== rightNode.value) { | |
return "your tree is not symmetric 🌴"; // return false | |
} | |
if (leftNode.left && rightNode.right) { | |
queue.unshift(leftNode.left); | |
queue.unshift(rightNode.right); | |
} else if (leftNode.left || rightNode.right) { | |
return "your tree is not symmetric 🌴"; // return false | |
} | |
if (leftNode.right && rightNode.left) { | |
queue.unshift(leftNode.right); | |
queue.unshift(rightNode.left); | |
} else if (leftNode.right || rightNode.left) { | |
return "your tree is not symmetric 🌴"; // return false | |
} | |
} | |
return "you have a perfectly symmetric tree! 🌲"; //return true | |
}; |
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