Solve Monty Hall Problem using Monte Carlo simulations

MontyHall.java

public class MontyHall {
	int usersChoice;
	int doorWithTheCar;
}

MontyHallMonteCarlo.java

import java.io.ObjectInputStream.GetField;
import java.util.Random;


public class MontyHallMonteCarlo {
	public MontyHall GetRandomScenario() {
		Random random = new Random();
		
		MontyHall game = new MontyHall();
		game.usersChoice = random.nextInt(3) + 1;
		game.doorWithTheCar = random.nextInt(3) + 1;
		
		return game;
	}
	
	public float SimulateWinSwitch(int n) {
		int sum = 0;

		for (int i = 0; i < n; i++) {
			int indicator = 0;
			
			MontyHall game = this.GetRandomScenario();
			
			if(game.doorWithTheCar != game.usersChoice){
				indicator = 1;
			}
			sum += indicator;
		}
		// By strong law of large numbers:
		return (float)sum / n;
	}
	
	public static void main(String[] args) {
		
		MontyHallMonteCarlo trial = new MontyHallMonteCarlo();
		
		System.out.println(trial.SimulateWinSwitch(10000));
		
	}
}