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Given a set of possibilities, determine the maximum reward in the possibilities given a certain constraint.
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/* | |
For this particular example the constraint is you cannot take two possibilities | |
that are next to each other. A real world example might be that you cannot invest multiple months | |
in a row and want to have the best chance at the best ROI. Kind of dumb but the point is | |
if there are constraints you want to track the best possible values for every sequence of moves, | |
only keeping track of the best possible outcomes | |
*/ | |
const bestOutcome = (arr) => { | |
// We want arr to be an array of possibilities | |
if (!Array.isArray(arr) || arr.length === 0) { | |
console.log('Argument is not array or array is empty'); | |
return; | |
} | |
/* | |
We want to take care of a few important conditions here. We don't want to run an expensive | |
iterative function if we don't have to, so if arr is only 1 or 2 indices long we know exactly | |
what value we want | |
*/ | |
const length = arr.length; | |
let nodeArr = []; // We will map out the indices of the possibilities array we choose to take. | |
let totalsArr = []; // We calculate our totals here, allowing us to only pass through the possiblities array once. | |
let i; | |
if (arr.length === 1) { | |
totalsArr[0] = arr[0]; | |
nodeArr[0] = 0; | |
} | |
if (arr.length === 2) { | |
totalsArr[0] = Math.max(arr[0], arr[1]); | |
nodeArr[0] = (arr[0] > arr[1]) ? 0 : 1; | |
} | |
totalsArr[0] = arr[0]; | |
totalsArr[1] = arr[1]; | |
let evenTrack; | |
let lastTaken = true; | |
for (i = 2; i < length; i++) { | |
totalsArr[i] = Math.max((arr[i] + totalsArr[i-2]), totalsArr[i -1]); | |
takeThis = (arr[i] + totalsArr[i-2] > totalsArr[i-1]); | |
if (takeThis) { | |
evenTrack = isEven(i); | |
if (evenTrack) { | |
if (evenTrack === lastTaken) { | |
nodeArr.push('e'); | |
} | |
else { | |
nodeArr.pop(); | |
nodeArr.push('s', i); | |
lastTaken = evenTrack; | |
} | |
} | |
else { | |
if (evenTrack === lastTaken) { | |
nodeArr.push('o'); | |
} | |
else { | |
nodeArr.pop(); | |
nodeArr.push('s', i); | |
lastTaken = evenTrack; | |
} | |
} | |
} | |
} | |
return [nodeArr, totalsArr, Math.max(totalsArr[length-1], totalsArr[length-2])]; | |
} | |
const isEven = (a) => a % 2 === 0; |
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Work in progress, trying to get the node array to come out right. Right now I am getting the indexes of where the program decided to switch tracks, which is progress