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import java.util.LinkedList; | |
/** | |
* Given a binary tree, design an algorithm which creates a linked list of all the nodes at each depth | |
* (e.g., if you have a tree with depth D,you'll have D linked lists). | |
* | |
* Time Complexity: O(n) | |
* Space Complexity: O(n) | |
*/ | |
public class Question4_4 { | |
public LinkedList<LinkedList<TreeNode>> levelOrderTraversal(TreeNode root) { | |
LinkedList<LinkedList<TreeNode>> traversal = new LinkedList<LinkedList<TreeNode>>(); | |
int currLevelNodes = 0; | |
int nextLevelNodes = 0; | |
LinkedList<TreeNode> queue = new LinkedList<TreeNode>(); | |
if (root != null) { | |
queue.addFirst(root); | |
++nextLevelNodes; | |
} | |
while (!queue.isEmpty()) { | |
if (currLevelNodes == 0) { | |
currLevelNodes = nextLevelNodes; | |
nextLevelNodes = 0; | |
traversal.add(new LinkedList<TreeNode>()); | |
} | |
TreeNode node = queue.removeLast(); | |
--currLevelNodes; | |
traversal.getLast().add(node); | |
if (node.left != null) { | |
queue.addFirst(node.left); | |
++nextLevelNodes; | |
} | |
if (node.right != null) { | |
queue.addFirst(node.right); | |
++nextLevelNodes; | |
} | |
} | |
return traversal; | |
} | |
public static void main(String[] args) { | |
Question4_4 question4_4 = new Question4_4(); | |
question4_4.levelOrderTraversal(null); | |
TreeNode root = new TreeNode(0); | |
root.left = new TreeNode(1); | |
root.right = new TreeNode(2); | |
root.left.right = new TreeNode(3); | |
root.right.right = new TreeNode(4); | |
LinkedList<LinkedList<TreeNode>> traversal = question4_4.levelOrderTraversal(root); | |
for (LinkedList<TreeNode> level : traversal) { | |
for (TreeNode node : level) { | |
System.out.print(node.value + "\t"); | |
} | |
System.out.println(); | |
} | |
} | |
} | |
class TreeNode { | |
int value; | |
TreeNode left; | |
TreeNode right; | |
public TreeNode() { | |
this(0, null, null); | |
} | |
public TreeNode(int value) { | |
this(value, null, null); | |
} | |
public TreeNode(int value, TreeNode left, TreeNode right) { | |
this.value = value; | |
this.left = left; | |
this.right = right; | |
} | |
} |
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