The staircase algorithm with javascript.

staircase.js

/**
 * Determine the number of stairs to print
 * The default stair has to have at least 1 space from the left
 * Other stairs should inherit the same syntax except the last one
 * 
 * First thing I had to do was initalize an empty stairs.
 * Create a loop based on the stairCaseLength Param.
 * Initialize two indexes. (One to handle the loop from 0 - stairCaseLength)(i) and the other to (decrement the stairCaseLength)(j)
 * For each case to be printed to the console, I had to use the .repeat method with (j - 1) to print the number of spaces the stairs(#)(i) should have. This would in turn make sure that the last stair to be printed has no spacing.
 * The stairs denoted by (#) are also printed out using the repeat method and it takes the (i + 1) as a param.
 * 
 * @param {number} stairCaseLength 
 * 
 */

function StairCase(stairCaseLength) {
  let stairs = "";
  for (let i = 0, j = stairCaseLength; i < stairCaseLength; i++, j--) {
    let stair = " ".repeat(j - 1) + "#".repeat(i + 1) + "\n";
    stairs += stair;
  }

  console.log(stairs.trimEnd());
}

StairCase(14);