ACM10499.c

ACM10499.c

#include <stdio.h>
#include <stdlib.h>

int main()
{
    long long int equal_parts;
    while(scanf("%lld", &equal_parts) != EOF)
    {
        if(equal_parts < 0)
            break;
        else if(equal_parts == 1)
            printf("0%%\n");
        else
            printf("%lld%%\n", equal_parts * 25);
    }

    return 0;
}

/*

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=16&problem=1440&mosmsg=Submission+received+with+ID+14345881

Coding reference
http://nc-oj.logdown.com/posts/2011/12/26/acm-10499-land-of-justice

http://olia14.pixnet.net/blog/post/12933913-c-acm-10499-the-land-of-justice


球體表面積公式為 4*π*R*R
1.如果切成 一半,可以想像多兩個大圓面積 為2*(R*R*π)
    ==>2*(R*R*π) /4*π*R*R =50%
 2.如果球體等分成3塊, 表面積會多 6*(1/2*R*R*π)  (想像每個切面都是1/2個大圓面積)
    ==>3*(R*R*π) /4*π*R*R =75%
 3.如果球體等分成3塊, 表面積會多 8*(1/2*R*R*π) 
    ==>4*(R*R*π) /4*π*R*R =100%



*/