Pythagorean Triplet Check

Prompt.md

Given an array of integers, determine whether it contains a Pythagorean triplet. Recall that a Pythogorean triplet (a, b, c) is defined by the equation a2+ b2= c2.

Example 1:
Input: [2, 5, 6, 7, -4, 3]
Output: true
Explanation: 3 squared + -4 squared = 5 squared

Example 2:
Input: [25, -4, 10, 7]
Output: false
Explanation: no Pythagorean triplet

Pseudo.txt

1. iterate over an array of integers
2. verify that they are integers
if they are integers then

simplified
arr [3, 4, 5, 2]
assuming all values are integers
find all possible sums of two numbers in array
push sums into new sumArray [7, 8, 5, 9, 6, 7]
square all values store in squaredArray
first iteration
3 + 4 = 7
3+ 5 = 8
3 + 2 = 5
4 + 5 = 9
4 + 2= 6
5 +2 =7
1 -> originalArray < iterating over this array to sum the values and store sums in new array sumArray
2 -> sumArray < iterate over this array > iterate back over the originalArray

PythagTripCheck.js

const originalArray = [3, 4, 5, 2]

const pythagTripCheck = (originalArray) => {
    let squaredArray = [];
    let sumArray = [];
    for(i = 0; i < originalArray.length; i++){
        let squared = Math.pow(originalArray[i], 2)
        squaredArray.push(squared)
    }
    let sum = originalArray[i] + originalArray[i+1];
    sumArray.push(sum)
console.log(sumArray, "SUM ARRAY")
    return sumArray
}

console.log(pythagTripCheck(originalArray))

// for(j = originArray[i+1], j < originalArray.length, j++) {
    //   //add value of num to the originalArray[j]
    //   // push the value of the sum into sumArray
    // }