Created
February 24, 2021 16:05
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Find duplicate element using Sorting approach
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#include <bits/stdc++.h> | |
using namespace std; | |
int sorting_duplicate(int arr[], int n) | |
{ | |
//Sort the array using STL sort function or write own sorting algorithm(merge sort or heap sort) | |
sort(arr, arr + n); | |
for (int i = 1; i < n; i++) | |
{ | |
//As the list is sorted,if two consecutive values are found, return the value as it is duplicate | |
if (arr[i] == arr[i + 1]) | |
return arr[i]; | |
} | |
// If duplicate value is not found, return -1 | |
return -1; | |
} | |
// Driver Code | |
int main() | |
{ | |
//Create an array with 1 duplicate value | |
int arr[7] = {1, 2, 3, 9, 3, 6, 5}; | |
//Calculate size of array | |
int n = sizeof(arr) / sizeof(arr[0]); | |
//Find out either the duplicate element present in the array or -1 | |
int duplicate = sorting duplicate(arr, n); | |
//Print duplicate array element | |
cout << duplicate << endl; | |
return 0; | |
} |
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