Created
February 23, 2010 15:29
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; Problem 6 | |
; The sum of the squares of the first ten natural numbers is, | |
; | |
; 1^2 + 2^2 + ... + 10^2 = 385 | |
(def natural-numbers (iterate inc 1)) | |
(def squares (map #(* % %) natural-numbers)) | |
(def sum-of-squares | |
(reduce + (take 10 squares))) | |
; The square of the sum of the first ten natural numbers is, | |
; | |
; (1 + 2 + ... + 10)^2 = 55^2 = 3025 | |
(def square-of-sum | |
(let [sum (reduce + (take 10 natural-numbers))] | |
(* sum sum))) | |
; Hence the difference between the sum of the squares of the first | |
; ten natural numbers and the square of the sum is 3025 - 385 = 2640. | |
(- square-of-sum sum-of-squares) | |
; Find the difference between the sum of the squares of the first one | |
; hundred natural numbers and the square of the sum. | |
(defn sum-of-squares* [n] | |
(reduce + (take n squares))) | |
(defn square-of-sum* [n] | |
(let [sum (reduce + (take n natural-numbers))] | |
(* sum sum))) | |
(defn diff [n] | |
(- (square-of-sum* n) (sum-of-squares* n))) |
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