Created
February 24, 2010 00:49
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; Problem 10 | |
; | |
; The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. | |
; | |
; Find the sum of all the primes below two million. | |
(defn prime? [x] | |
(cond (< x 2) false | |
(= x 2) true | |
(even? x) false | |
:else (let [boundary (inc (bigint (Math/sqrt x))) | |
candidates (range 3 boundary 2)] | |
(empty? (drop-while #(pos? (mod x %)) candidates))))) | |
; Slow version, test all odd numbers | |
(defn sum-of-primes-upto [limit] | |
(loop [x 3 sum 2] | |
(if (< x limit) | |
(if (prime? x) | |
(recur (+ x 2) (+ x sum)) | |
(recur (+ x 2) sum)) | |
sum))) | |
; Fast version, use Sieve of Eratosthenes | |
(defn sum-of-primes-upto* [limit] | |
(let [sieve (doto (java.util.BitSet.) (.set 1))] ; mark 1 as non-prime, rest as candidates, | |
(loop [n 3 sum 2] ; skipping even numbers | |
(cond | |
(>= n limit) | |
sum | |
(false? (.get sieve n)) ; n is a prime | |
(do | |
(doseq [x (range (+ n n) limit n)] | |
(.set sieve x)) ; mark all multiples as non-prime | |
(recur (+ n 2) (+ sum n))) | |
(true? (.get sieve n)) ; previously marked non-prime | |
(recur (+ n 2) sum))))) | |
(def answer (future (sum-of-primes-upto 2000000))) | |
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