my solution for codility task

OddOccurrencesInArray python

// find odd element in array
def solution(A):
    accessed = [False] * len(A)
    randit = len(A)
    for a in range(len(A)):
        if accessed[a] == False:
            for b in range(len(A)):
                if a == b:
                    continue
                if accessed[b] == False:
                    if A[a] == A[b]:
                        accessed[a] = True
                        accessed[b] = True
            if(accessed[a] == False):
                return A[a]
B = [6,2,9,2,3,6,7,3,1,7,9,1,5]
print(solution(B))