Created
February 15, 2016 15:25
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Given a square matrix of size N×NN×N, calculate the absolute difference between the sums of its diagonals. Input Format The first line contains a single integer, NN. The next NN lines denote the matrix's rows, with each line containing NN space-separated integers describing the columns. Output Format Print the absolute difference between the two…
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import java.io.*; | |
import java.util.*; | |
import java.text.*; | |
import java.math.*; | |
import java.lang.*;; | |
import java.util.regex.*; | |
public class Solution { | |
public static void main(String[] args) { | |
Scanner in = new Scanner(System.in); | |
int n = in.nextInt(); | |
int a[][] = new int[n][n]; | |
int primaryDiagSum = 0; | |
int secondaryDiagSum = 0; | |
for(int a_i=0; a_i < n; a_i++){ | |
for(int a_j=0; a_j < n; a_j++){ | |
a[a_i][a_j] = in.nextInt(); | |
if(a_i == a_j){ | |
primaryDiagSum += a[a_i][a_j]; | |
} | |
if(a_i+1+a_j+1 == n+1){ | |
secondaryDiagSum += a[a_i][a_j]; | |
} | |
} | |
} | |
System.out.println(Math.abs(primaryDiagSum - secondaryDiagSum)); | |
} | |
} |
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