Created
December 29, 2015 02:52
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public class Solution { | |
public int maxProfit(int[] prices) { | |
if(prices==null || prices.length==0) return 0; | |
//max profit to complete an transpaction no later than the i-th day | |
int min = prices[0]; | |
int[] pre = new int[prices.length]; | |
for(int i=1; i<prices.length; i++){ | |
min = Math.min(min, prices[i]); | |
pre[i] = Math.max(pre[i-1],prices[i]-min); | |
} | |
//max profit to complete an transaction start from the i-th day | |
int max = prices[prices.length-1]; | |
int[] back = new int[prices.length]; | |
for(int i=prices.length-2; i>=0; i--){ | |
max = Math.max(max, prices[i]); | |
back[i] = Math.max(back[i+1], max-prices[i]); | |
} | |
//choose the max profits of two transactions | |
//one ends no later than the i-th day | |
//one starts at or after the i-th day | |
int sum = 0; | |
for(int i=0; i<prices.length; i++){ | |
sum = Math.max(pre[i] + back[i], sum); | |
} | |
return sum; | |
} | |
} |
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