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@hyeonjae
Created June 1, 2015 02:33
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MD5 standalone in Swift 1.2
/*
* http://rosettacode.org/wiki/MD5/Implementation#Swift
* https://github.com/krzyzanowskim/CryptoSwift/tree/master/CryptoSwift
* MD5 - no need to external library version
*/
import Foundation
let shift : [UInt32] = [7, 12, 17, 22, 5, 9, 14, 20, 4, 11, 16, 23, 6, 10, 15, 21]
let table: [UInt32] = (0 ..< 64).map { UInt32(0x100000000 * abs(sin(Double($0 + 1)))) }
func md5(var message: [UInt8]) -> [UInt8] {
var messageLenBits = UInt64(message.count) * 8
message.append(0x80)
while message.count % 64 != 56 {
message.append(0)
}
var lengthBytes = [UInt8](count: 8, repeatedValue: 0)
UnsafeMutablePointer<UInt64>(lengthBytes).memory = messageLenBits.littleEndian
message += lengthBytes
var a : UInt32 = 0x67452301
var b : UInt32 = 0xEFCDAB89
var c : UInt32 = 0x98BADCFE
var d : UInt32 = 0x10325476
for chunkOffset in stride(from: 0, to: message.count, by: 64) {
let chunk = UnsafePointer<UInt32>(UnsafePointer<UInt8>(message) + chunkOffset)
let originalA = a
let originalB = b
let originalC = c
let originalD = d
for j in 0 ..< 64 {
var f : UInt32 = 0
var bufferIndex = j
let round = j >> 4
switch round {
case 0:
f = (b & c) | (~b & d)
case 1:
f = (b & d) | (c & ~d)
bufferIndex = (bufferIndex*5 + 1) & 0x0F
case 2:
f = b ^ c ^ d
bufferIndex = (bufferIndex*3 + 5) & 0x0F
case 3:
f = c ^ (b | ~d)
bufferIndex = (bufferIndex * 7) & 0x0F
default:
assert(false)
}
let sa = shift[(round<<2)|(j&3)]
let tmp = a &+ f &+ UInt32(littleEndian: chunk[bufferIndex]) &+ table[j]
a = d
d = c
c = b
b = b &+ (tmp << sa | tmp >> (32-sa))
}
a = a &+ originalA
b = b &+ originalB
c = c &+ originalC
d = d &+ originalD
}
var result = [UInt8](count: 16, repeatedValue: 0)
for (i, n) in enumerate([a, b, c, d]) {
UnsafeMutablePointer<UInt32>(result)[i] = n.littleEndian
}
return result
}
func toHexString(bytes: [UInt8]) -> String {
return "".join(bytes.map { String(format:"%02x", $0) })
}
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