身份证校验码计算

id_check.py

#! /usr/bin/env python3
# -*- coding: utf-8 -*-

from functools import reduce

# 系数，fix =  (2 ** (17 - i) % 11 for i in range(17))
fix = (7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2)

# 根据身份证号前17位计算第18位
def get_check_code(id_head):
    if len(id_head) != 17:
        return -1
    if not id_head.isdigit():
        return -1
    _sum = reduce(lambda x, y: x + y[0] * int(y[1]), zip(fix, id_head), 0)
    _result = 12 - _sum % 11
    return _result - 11 if _result > 10 else _result

# 判断输入的身份证号是否为合法的身份证号
def check_id(id_num):
    if len(id_num) != 18:
        return False
    if id_num[:17].isdigit():
        check_code = get_check_code(id_num[:17])
    else:
        return False
    if check_code == 10 and id_num[17] == 'X' or (
       check_code == int(id_num[17])): 
        return True
    return False

if __name__ == '__main__':
    while True:
        input_id = input().strip()
        if input_id == '00':
            break
        print(check_id(input_id), get_check_code(input_id[:17]))