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@iRusel
Created June 24, 2017 14:37
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word; end;
VAR
n,i,srednya_zp:integer;
man:array [1..15] of rabochi;
begin
writeln('skolko rabochih?');
readln(n);
for i:=1 to n do
with man[i] do
begin
writeln('Familia rabochego #',i);
readln(surname);
writeln('Ego zarplata:');
readln(zp);
writeln('Skolko let rabotaet?');
readln(stazh);
writeln('Dolzhnost`:');
readln(profession);
end;
srednya_zp:=0;
for i:=1 to n do
begin
WITH man[i] do begin srednya_zp:=srednya_zp+zp;
srednya_zp:=srednya_zp div n;
writeln;
writeln('Bolee 10 let prorabotali:');
write('Surname':13);
write('Zarplata':13);
write('Stazh raboti':13);
writeln('Dolzhnost':13);
end;
end;
for i:=1 to n do
with man[i] do
If stazh>10 then
begin
write(surname:12);
write(zp:12);
write(stazh:12);
writeln(profession:12);
end;
writeln;
writeln('Ih zarplata nizhe srednei:');
for i:=1 to n do
with man[i] do
If zp<srednya_zp then writeln(surname);
readln;
end.
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