Loop Drills

ComputeAverage.js

// Compute Average Drill

function average(numbers) {
  var avg = numbers.reduce(function sum(total,num) {
    return total + num;
  })
  return avg/numbers.length;
}

// I used the .reduce() method with .length


// Curriculum Solution

function average(numbers) {
  var total = numbers[0];
  for (var i=1; i < numbers.length; i++) {
    total+= numbers[i];
  }
  return total/number.length;
}

// 1. Set the value of the first number.
// 2. Then add each of the remaining numbers to total.
// 3. Return the total divided by the length of array.

FizzBuzz.js

// FizzBuzz Drill


function fizzBuzz(countTo) {
  var currentNum = countTo[0];
  var div3 = num % 3 === 0;
  var div5 = num % 5 === 0;
  for (var i=0; i<=countTo.length; i++);
  return countTo.map(function(sub) {
      if (countTo[i] = div3) {
    currentNum = "fizz";
  }
  if (countTo[i] = div5) {
    currentNum = "buzz";
  }
  if (countTo[i] = div3 && div5) {
    currentNum = "fizzbuzz";
  }
  })
}

// Couldnt figure it out, was using .map() method

// Solution

function fizzBuzz(countTo) {
  var result = [];
  for (var i=1; i <= countTo; i++) {
    if (i % 15 === 0) {
      result.push('fizzbuzz'); 
    }
    else if (i % 5 === 0) {
      result.push('buzz');
    }
    else if (i % 3 === 0) {
      result.push('fizz');
    }
    else {
      result.push(i);
    }
  }
  return result;
}
// 1. Create an empty array that will contain results
// 2. Count from 1 to `countTo`, and for each number, add the number or its substitution (fizz, buzz, fizzbuzz)
//    to the result array.

MaxMinDrill.js

// Max/Min without Sort Drill

// Create two functions, one to return the max number on a list and a second one to return the min


function max(numbers) {
 for (var i=0; i <= numbers; i++);
  return numbers.find(max);
}


function min(numbers) {
 // your code here
}

// Couldnt solve at 20 mins

// 'numbers[i]' tells the function what ever position 'i' is at, if that value is > (greater than), then set as currentMax

// Solution

function max(numbers) {
  var currentMax = numbers[0];
  for (var i=0; i <= numbers.length; i++) {
    if (numbers[i] > currentMax) {
       currentMax = numbers[i];
    }
  }
  return currentMax;
}
// 1. Set 'currentMax' to the value of first item so we can have a number to compare it to
// 2. Loop through 'numbers' comparing each item to 'currentMax'
// 3. 'if' the item is greater than 'currentMax', set 'currentMax' to that number
// 4. return currentMax

function min(numbers) {
  var currentMin = numbers[0];
  for (var i=0; i <= numbers.length; i++) {
    if (numbers[i] < currentMin) {
       currentMin = numbers[i];
    }
  }
  return currentMin;
}

// 1. Set 'currentMin' to the value of first item in 'numbers'
// 2. Loop through 'numbers' comparing each item to 'currentMin'
// 3. 'if' the item is less than 'currentMin', set 'currentMin' to that number