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#数组 #螺旋矩阵 #leetcode
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class Solution { | |
public: | |
vector<vector<int>> generateMatrix(int n) { | |
// 行 列 | |
vector<vector<int>> mat; | |
for (int i = 0; i < n; ++i) { | |
vector<int> tmp; | |
for (int j = 0; j < n; ++j) | |
tmp.push_back(0); | |
mat.push_back(tmp); | |
} | |
assert(mat.size() == n && "mat size not equal to n"); | |
// right down left up | |
int step[4][2] = {{0,1}, {1,0}, {0, -1}, {-1,0}}; | |
int size = n * n; | |
int num = 1; | |
int row = 0, col = 0; | |
int k_step = 0; | |
while (num <= size) { | |
mat.at(row).at(col) = num++; | |
int next_row = row + step[k_step][0]; | |
int next_col = col + step[k_step][1]; | |
if (next_row < 0 || next_row >= n || next_col < 0 || next_col >= n) | |
k_step = (k_step + 1) % 4; | |
else if (mat.at(next_row).at(next_col) != 0) | |
k_step = (k_step + 1) % 4; | |
// update | |
row = row + step[k_step][0]; | |
col = col + step[k_step][1]; | |
} | |
return mat; | |
} | |
}; |
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