$3x^2-5x+2=x^2+x+2$
2; 3
4; 5
1; -2
$x^2+3x+1=x+1$
$3(1+2x^2)=3x^2-5(4x^2-1)$
$\sqrt{5x+1}+\sqrt{x+6}=\sqrt{2x+3}+\sqrt{6x-2}$
$\sqrt{2x+14}-\sqrt{3x+1}=2$
$\sqrt{x+7+\sqrt{x+10}}=3$
$$\frac 23$$
$3x^2-5x+2=x^2+x+2$
2; 3
4; 5
1; -2
$x^2+3x+1=x+1$
$3(1+2x^2)=3x^2-5(4x^2-1)$
$\sqrt{5x+1}+\sqrt{x+6}=\sqrt{2x+3}+\sqrt{6x-2}$
$\sqrt{2x+14}-\sqrt{3x+1}=2$
$\sqrt{x+7+\sqrt{x+10}}=3$
$$\frac 23$$