Show number of each weekday in a year

days.py

from datetime import datetime, timedelta
from tabulate import tabulate
from calendar import day_name
import sys

def wd(d):
  return list(day_name)[d]

def sorted_week():
  return sorted([(j+1)%7 for j in range(7)], key=lambda n: (n+1)%7)

days = { i: 0 for i in range(7) }

try:
  year = int(sys.argv[1])
except:
  year = datetime.today().year

d = datetime(year, 1, 1)
while d != datetime(year+1, 1, 1):
  days[d.weekday()] += 1
  d += timedelta(days=1)

print "Year: %s" % year
print tabulate([[wd(i), days[i]] for i in sorted_week()], headers=['Weekday', 'Count'])