Created
May 31, 2021 14:38
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LeetCode 2. Add Two Numbers
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/** | |
* Definition for singly-linked list. | |
* public class ListNode { | |
* int val; | |
* ListNode next; | |
* ListNode() {} | |
* ListNode(int val) { this.val = val; } | |
* ListNode(int val, ListNode next) { this.val = val; this.next = next; } | |
* } | |
*/ | |
class Solution { | |
public ListNode addTwoNumbers(ListNode l1, ListNode l2) { | |
ListNode c1 = null; | |
ListNode c2 = null; | |
ListNode s = null; | |
ListNode p = null; | |
ListNode n = null; | |
int overflow = 0; | |
c1 = l1; | |
c2 = l2; | |
while(c1 != null || c2 != null){ | |
int sum =0; | |
if( c1 == null ){ | |
sum = c2.val + overflow; | |
}else if( c2 == null){ | |
sum = c1.val + overflow; | |
}else{ | |
sum = c1.val + c2.val + overflow; | |
} | |
if( sum > 9 ){ | |
n = new ListNode(sum-10); | |
overflow = 1; | |
}else{ | |
n = new ListNode(sum); | |
overflow = 0; | |
} | |
if( p != null ){ | |
p.next = n; | |
} | |
p = n; | |
if( s == null ){ | |
s = p; | |
} | |
c1 = (c1 == null || c1.next == null)? null: c1.next; | |
c2 = (c2 == null || c2.next == null)? null: c2.next;; | |
} | |
if(overflow > 0){ | |
n = new ListNode(1); | |
p.next = n; | |
} | |
return s; | |
} | |
} |
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