readme.md

https://superuser.com/questions/229773/run-command-on-startup-login-mac-os-x

remote_logout.py

import socket
from http.server import BaseHTTPRequestHandler, HTTPServer
import subprocess

class RequestHandler(BaseHTTPRequestHandler):
    def do_GET(self):
        client_ip = self.client_address[0]
        if self.path == '/logout':
            user_id = subprocess.check_output("id -u assistant", shell=True).decode().strip()
            command = f"launchctl bootout gui/{user_id}"

            # Log the client IP and the command before executing
            log_message = f"Request from {client_ip}: Executing command '{command}'"
            print(log_message)

            # Execute the command
            subprocess.run(command, shell=True)

            # Respond to the client
            self.send_response(200)
            self.send_header('Content-type', 'text/plain')
            self.end_headers()
            response_message = f'Logout command executed for IP: {client_ip}'
            self.wfile.write(response_message.encode())
        else:
            self.send_response(404)
            self.end_headers()
            self.wfile.write(b'Not Found')

def run(server_class=HTTPServer, handler_class=RequestHandler, port=51789):
    ip = '0.0.0.0'  # Bind to all available interfaces
    server_address = (ip, port)
    httpd = server_class(server_address, handler_class)
    try:
        print(f"Starting http server on {ip}:{port}")
        httpd.serve_forever()
    except KeyboardInterrupt:
        pass
    httpd.server_close()
    print("Server stopped.")

if __name__ == '__main__':
    run()