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Unique Morse Code Words
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let dictMap: [Character: String] = [ | |
"a":".-", | |
"b":"-...", | |
"c":"-.-.", | |
"d": "-..", | |
"e":".", | |
"f":"..-.", | |
"g":"--.", | |
"h":"....", | |
"i":"..", | |
"j":".---", | |
"k":"-.-", | |
"l":".-..", | |
"m":"--", | |
"n":"-.", | |
"o":"---", | |
"p":".--.", | |
"q":"--.-", | |
"r":".-.", | |
"s":"...", | |
"t":"-", | |
"u":"..-", | |
"v":"...-", | |
"w":".--", | |
"x":"-..-", | |
"y":"-.--", | |
"z":"--.." | |
] | |
func uniqueMorse(_ words: [String]) -> Int { | |
guard !words.isEmpty else { return 0 } | |
var result = Set<String>() | |
words.forEach { word in | |
var morse = "" | |
word.forEach({ character in | |
morse += dictMap[character] ?? ".-" | |
}) | |
result.insert(morse) | |
} | |
return result.count | |
} | |
uniqueMorse(["gin", "zen", "gig", "msg"]) |
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International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on.
For convenience, the full table for the 26 letters of the English alphabet is given below:
[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cab" can be written as "-.-.-....-", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.
Return the number of different transformations among all words we have.
Note:
The length of words will be at most 100.
Each words[i] will have length in range [1, 12].
words[i] will only consist of lowercase letters.