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October 23, 2016 16:52
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It Takes Two Long Form
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| let expert = Expert() | |
| let character = Character() | |
| var gemCon = 0 | |
| var switchCon = 0 | |
| func expertNav() { | |
| expert.turnLeft() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.turnRight() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.turnLeft() | |
| expert.turnLockDown() | |
| expert.turnLockDown() | |
| expert.turnRight() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.turnRight() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.turnRight() | |
| expert.moveForward() | |
| expert.moveForward() | |
| expert.turnLeft() | |
| expert.turnLockUp() | |
| } | |
| func characterNav() { | |
| character.moveForward() | |
| character.moveForward() | |
| if character.isOnGem { | |
| character.collectGem() | |
| gemCon += 1 | |
| character.moveForward() | |
| character.moveForward() | |
| } | |
| if character.isOnClosedSwitch { | |
| character.toggleSwitch() | |
| switchCon += 1 | |
| } | |
| } | |
| while gemCon < 1 && switchCon < 1 { | |
| expertNav() | |
| characterNav() | |
| } |
Essentially reducing the lines of code necessary for completing the task.
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I wrote this in longer form. I feel like I can improve it by counting the expert instance's steps. Going to give that a whirl here.