Open a URL in Safari or App (Helper)

OpenURL.swift

enum OpenURL {
    enum Scheme {
        case url(String)
        case tel(String)
        case app(String)
    }
    
    static func open(scheme: OpenURL.Scheme, completion: ((Bool) -> Void)? = nil) {
        let application = UIApplication.shared
        let url: URL
        switch scheme {
        case .tel(let phoneNumber):
            guard let finalUrl = URL(string: "tel://\(phoneNumber)") else { return }
            url = finalUrl
        case .url(let urlString):
            guard let finalUrl = URL(string: urlString) else { return }
            url = finalUrl
        case .app(let urlString):
            guard let finalUrl = URL(string: urlString) else { return }
            if application.canOpenURL(finalUrl) {
                application.open(finalUrl)
            } else {
                completion?(false)
            }
            return
        }
        application.open(url, options: [:], completionHandler: completion)
    }
}