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Cross counting X pattern in a vector
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#include <iostream> | |
#include <vector> | |
using namespace std; | |
// Defining rows and columns of | |
// vector of vectors | |
int main() | |
{ | |
int diagonalRight = 0; | |
int diagonalLeft = 0; | |
int absDifference = 0; | |
// Initializing the vector of vectors | |
vector<vector<int>> vect | |
{ | |
{1, 2, 3}, | |
{4, 5, 6}, | |
{10, 8, 9} | |
}; | |
// Print the values we just declared | |
for (int i = 0; i < vect.size(); ++i) | |
{ | |
for (int j = 0; j < vect[i].size(); ++j) | |
{ | |
if (i == j) | |
{ | |
diagonalRight += vect[i][j]; | |
} | |
if (i == vect.size() - 1 - j) | |
{ | |
cout << "vect[" << i << "]" << "[" << j << "]" << endl; | |
diagonalLeft += vect[i][j]; | |
} | |
} | |
} | |
absDifference = diagonalRight - diagonalLeft; | |
if (absDifference < 0) | |
{ | |
absDifference *= -1; | |
} | |
cout << absDifference << endl; | |
return 0; | |
} |
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