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LeetCode: Graph
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// Source: https://leetcode.com/problems/symmetric-tree/ | |
/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
private: | |
bool symmetry(TreeNode* l, TreeNode* r) { | |
if (l == nullptr && r == nullptr) // the parent is a leaf. | |
return true; | |
if (l == nullptr || r == nullptr) // skew | |
return false; | |
if (l->val != r->val) | |
return false; | |
return symmetry(l->left, r->right) && symmetry(l->right, r->left); | |
} | |
public: | |
bool isSymmetric(TreeNode* root) { | |
if (root == nullptr) | |
return true; | |
return symmetry(root->left, root->right); | |
} | |
}; |
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// Source: https://leetcode.com/problems/binary-tree-level-order-traversal/ | |
#include <iostream> | |
#include <vector> | |
#include <queue> | |
using namespace std; | |
// Definition for a binary tree node. | |
struct TreeNode | |
{ | |
int val; | |
TreeNode *left; | |
TreeNode *right; | |
TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
}; | |
class Solution | |
{ | |
public: | |
vector<vector<int>> levelOrder(TreeNode *root) | |
{ | |
vector<vector<int>> res; | |
if (root == NULL) | |
return res; | |
queue<TreeNode *> q; | |
q.push(root); | |
while (!q.empty()) | |
{ | |
vector<int> level; | |
int n = q.size(); | |
for (int i = 0; i < n; i++) | |
{ | |
auto u = q.front(); | |
level.push_back(u->val); | |
if (u->left) | |
q.push(u->left); | |
if (u->right) | |
q.push(u->right); | |
q.pop(); | |
} | |
res.push_back(level); | |
} | |
return res; | |
} | |
}; |
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// Source: https://leetcode.com/problems/binary-tree-level-order-traversal-ii/ | |
/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
vector<vector<int>> levelOrderBottom(TreeNode* root) { | |
vector<vector<int>> sol; | |
if (root == nullptr) return sol; | |
queue<TreeNode *> q; | |
q.push(root); | |
while (!q.empty()) { | |
vector<int> level; | |
int n = q.size(); | |
for (int i = 0; i < n; i++) { | |
auto s = q.front(); | |
level.push_back(s->val); | |
if (s->left) | |
q.push(s->left); | |
if (s->right) | |
q.push(s->right); | |
q.pop(); | |
} | |
sol.push_back(level); | |
} | |
reverse(sol.begin(), sol.end()); | |
return sol; | |
} | |
}; |
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// Source: https://leetcode.com/problems/binary-tree-right-side-view/ | |
/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
vector<int> rightSideView(TreeNode* root) { | |
vector<int> res; | |
if (!root) return res; | |
queue<TreeNode *> q; | |
q.push(root); | |
while (!q.empty()) { | |
int n = q.size(); | |
int r = INT_MIN; // sentinel | |
while (n--) { | |
auto u = q.front(); | |
q.pop(); | |
r = u->val; | |
if (u->left) q.push(u->left); | |
if (u->right) q.push(u->right); | |
} | |
if (r != INT_MIN) | |
res.push_back(r); | |
} | |
return res; | |
} | |
}; |
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// Source: https://leetcode.com/problems/subtree-of-another-tree/ | |
/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
private: | |
bool isIdentical(TreeNode* s, TreeNode* t) { | |
if (s == nullptr && t == nullptr) | |
return true; | |
if (s == nullptr || t == nullptr) | |
return false; | |
if (s->val == t->val) | |
return isIdentical(s->left, t->left) && | |
isIdentical(s->right, t->right); | |
return false; | |
} | |
public: | |
bool isSubtree(TreeNode* s, TreeNode* t) { | |
if (s == nullptr || t == nullptr) | |
return false; | |
if (s->val == t->val && | |
isIdentical(s->left, t->left) && | |
isIdentical(s->right, t->right)) | |
return true; | |
return isSubtree(s->left, t) || isSubtree(s->right, t); | |
} | |
}; |
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// Source: https://leetcode.com/problems/is-graph-bipartite/ | |
class Solution { | |
public: | |
bool isBipartite(vector<vector<int>>& graph) { | |
int n = graph.size(); | |
vector<bool> visited(n); | |
vector<int> color(n); | |
fill(color.begin(), color.end(), -1); | |
queue<int> q; | |
bool isbipartite = true; | |
auto bfs = [&] (int source) { | |
q.push(source); | |
visited[source] = true; | |
color[source] = 0; | |
while (!q.empty() && isbipartite) { | |
int u = q.front(); | |
q.pop(); | |
for (int v: graph[u]) { | |
if (visited[v]) { | |
if (color[u] == color[v]) { | |
isbipartite = false; | |
break; | |
} | |
continue; | |
} | |
visited[v] = true; | |
color[v] = 1 ^ color[u]; | |
q.push(v); | |
} | |
} | |
}; | |
for (int u = 0; u < n; u++) | |
if (color[u] == -1) | |
bfs(u); | |
return isbipartite; | |
} | |
}; |
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// Source: https://leetcode.com/problems/leaf-similar-trees/ | |
/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
private: | |
vector<int> dfs(TreeNode* root) { | |
vector<int> res; | |
stack<TreeNode*> s; | |
s.push(root); | |
while (!s.empty()) { | |
auto u = s.top(); | |
s.pop(); | |
if (u->left == nullptr && u->right == nullptr) | |
res.push_back(u->val); | |
else { | |
if (u->left) s.push(u->left); | |
if (u->right) s.push(u->right); | |
} | |
} | |
return res; | |
} | |
public: | |
bool leafSimilar(TreeNode* root1, TreeNode* root2) { | |
auto v = dfs(root1); | |
auto w = dfs(root2); | |
bool similar = v.size() == w.size(); | |
if (!similar) return similar; | |
for (int i = 0, n = v.size(); i < n; i++) { | |
if (v[i] != w[i]) { | |
similar = false; | |
break; | |
} | |
} | |
return similar; | |
} | |
}; |
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// Source: https://leetcode.com/problems/increasing-order-search-tree/ | |
/** | |
* Definition for a binary tree node. | |
* struct TreeNode { | |
* int val; | |
* TreeNode *left; | |
* TreeNode *right; | |
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} | |
* }; | |
*/ | |
class Solution | |
{ | |
private: | |
TreeNode* last = nullptr; // last node in the tree built so far. | |
public: | |
TreeNode* increasingBST(TreeNode* root) | |
{ | |
if (root->left == nullptr && root->right == nullptr) // leaf | |
{ | |
last = root; | |
return root; | |
} | |
if (root->left != nullptr) | |
{ | |
auto u = increasingBST(root->left); | |
last->right = root; | |
last = root; | |
root->left = nullptr; | |
root = u; | |
} | |
root->right = increasingBST(root->right); | |
return root; | |
} | |
}; |
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