Created
March 30, 2021 09:07
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Write a program to print out all Armstrong numbers between 1 and 500. If sum of cubes of each digit of the number is equal to the number itself, then the number is called an Armstrong number. For example, 153 = ( 1 * 1 * 1 ) + ( 5 * 5 * 5 ) + ( 3 * 3 * 3 )
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//π’ππ©ππ€π 1 | |
#include <stdio.h> | |
#include<math.h> | |
int main() | |
{ | |
int num, d1, d2, d3, sum, num2; | |
//d1 d2 d2 is first,second ,third digit of num | |
// eg num=34 then d1=0 d2=3 ,d3=4 | |
for (num = 1; num <= 500; num++) | |
{ | |
d3 = num % 10; | |
num2 = num / 10; | |
d2 = num2 % 10; | |
d1 = num2 / 10; | |
sum = pow(d1, 3) + pow(d2, 3) + pow(d3, 3); | |
if (sum == num) | |
{ | |
printf("%d\n",sum); | |
} | |
} | |
} | |
----->>> | |
//π’ππ©ππ€π 2 | |
#include <stdio.h> | |
#include <math.h> | |
int main() | |
{ | |
int num, sum = 0, temp, rem, cub; | |
for (num = 1; num <= 500; num++) | |
{ | |
temp=num; | |
while (num != 0) | |
{ | |
rem = num % 10; | |
cub = pow(rem, 3); | |
sum = sum + cub; | |
num = num / 10; | |
} | |
if (sum == temp) | |
{ | |
printf("%d\n", sum); | |
} | |
sum = 0; | |
num=temp; | |
} | |
} |
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