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jalotra/human_eval_test_data.txt

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Human Eval Human Readable Tests(Total of 164) (Test Data Repo : https://github.com/openai/human-eval)
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human_eval_test_data.txt
---------------------------------------WRITING INFO ABOUT TEST 0----------------------------------------
-------------PROMPT----------------
from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)
True
"""
--------CANONICAL SOLUTION--------
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
distance = abs(elem - elem2)
if distance < threshold:
return True
return False
---------------------------------------INFO ABOUT TEST 0 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 1----------------------------------------
-------------PROMPT----------------
from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
>>> separate_paren_groups('( ) (( )) (( )( ))')
['()', '(())', '(()())']
"""
--------CANONICAL SOLUTION--------
result = []
current_string = []
current_depth = 0
for c in paren_string:
if c == '(':
current_depth += 1
current_string.append(c)
elif c == ')':
current_depth -= 1
current_string.append(c)
if current_depth == 0:
result.append(''.join(current_string))
current_string.clear()
return result
---------------------------------------INFO ABOUT TEST 1 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 2----------------------------------------
-------------PROMPT----------------
def truncate_number(number: float) -> float:
""" Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
>>> truncate_number(3.5)
0.5
"""
--------CANONICAL SOLUTION--------
return number % 1.0
---------------------------------------INFO ABOUT TEST 2 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 3----------------------------------------
-------------PROMPT----------------
from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return True. Otherwise it should return False.
>>> below_zero([1, 2, 3])
False
>>> below_zero([1, 2, -4, 5])
True
"""
--------CANONICAL SOLUTION--------
balance = 0
for op in operations:
balance += op
if balance < 0:
return True
return False
---------------------------------------INFO ABOUT TEST 3 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 4----------------------------------------
-------------PROMPT----------------
from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
>>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
1.0
"""
--------CANONICAL SOLUTION--------
mean = sum(numbers) / len(numbers)
return sum(abs(x - mean) for x in numbers) / len(numbers)
---------------------------------------INFO ABOUT TEST 4 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 5----------------------------------------
-------------PROMPT----------------
from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
--------CANONICAL SOLUTION--------
if not numbers:
return []
result = []
for n in numbers[:-1]:
result.append(n)
result.append(delimeter)
result.append(numbers[-1])
return result
---------------------------------------INFO ABOUT TEST 5 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 6----------------------------------------
-------------PROMPT----------------
from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
>>> parse_nested_parens('(()()) ((())) () ((())()())')
[2, 3, 1, 3]
"""
--------CANONICAL SOLUTION--------
def parse_paren_group(s):
depth = 0
max_depth = 0
for c in s:
if c == '(':
depth += 1
max_depth = max(depth, max_depth)
else:
depth -= 1
return max_depth
return [parse_paren_group(x) for x in paren_string.split(' ') if x]
---------------------------------------INFO ABOUT TEST 6 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 7----------------------------------------
-------------PROMPT----------------
from typing import List
def filter_by_substring(strings: List[str], substring: str) -> List[str]:
""" Filter an input list of strings only for ones that contain given substring
>>> filter_by_substring([], 'a')
[]
>>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
['abc', 'bacd', 'array']
"""
--------CANONICAL SOLUTION--------
return [x for x in strings if substring in x]
---------------------------------------INFO ABOUT TEST 7 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 8----------------------------------------
-------------PROMPT----------------
from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
>>> sum_product([1, 2, 3, 4])
(10, 24)
"""
--------CANONICAL SOLUTION--------
sum_value = 0
prod_value = 1
for n in numbers:
sum_value += n
prod_value *= n
return sum_value, prod_value
---------------------------------------INFO ABOUT TEST 8 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 9----------------------------------------
-------------PROMPT----------------
from typing import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
--------CANONICAL SOLUTION--------
running_max = None
result = []
for n in numbers:
if running_max is None:
running_max = n
else:
running_max = max(running_max, n)
result.append(running_max)
return result
---------------------------------------INFO ABOUT TEST 9 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 10----------------------------------------
-------------PROMPT----------------
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
>>> make_palindrome('')
''
>>> make_palindrome('cat')
'catac'
>>> make_palindrome('cata')
'catac'
"""
--------CANONICAL SOLUTION--------
if not string:
return ''
beginning_of_suffix = 0
while not is_palindrome(string[beginning_of_suffix:]):
beginning_of_suffix += 1
return string + string[:beginning_of_suffix][::-1]
---------------------------------------INFO ABOUT TEST 10 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 11----------------------------------------
-------------PROMPT----------------
from typing import List
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
--------CANONICAL SOLUTION--------
def xor(i, j):
if i == j:
return '0'
else:
return '1'
return ''.join(xor(x, y) for x, y in zip(a, b))
---------------------------------------INFO ABOUT TEST 11 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 12----------------------------------------
-------------PROMPT----------------
from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a'
>>> longest(['a', 'bb', 'ccc'])
'ccc'
"""
--------CANONICAL SOLUTION--------
if not strings:
return None
maxlen = max(len(x) for x in strings)
for s in strings:
if len(s) == maxlen:
return s
---------------------------------------INFO ABOUT TEST 12 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 13----------------------------------------
-------------PROMPT----------------
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
--------CANONICAL SOLUTION--------
while b:
a, b = b, a % b
return a
---------------------------------------INFO ABOUT TEST 13 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 14----------------------------------------
-------------PROMPT----------------
from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
--------CANONICAL SOLUTION--------
result = []
for i in range(len(string)):
result.append(string[:i+1])
return result
---------------------------------------INFO ABOUT TEST 14 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 15----------------------------------------
-------------PROMPT----------------
def string_sequence(n: int) -> str:
""" Return a string containing space-delimited numbers starting from 0 upto n inclusive.
>>> string_sequence(0)
'0'
>>> string_sequence(5)
'0 1 2 3 4 5'
"""
--------CANONICAL SOLUTION--------
return ' '.join([str(x) for x in range(n + 1)])
---------------------------------------INFO ABOUT TEST 15 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 16----------------------------------------
-------------PROMPT----------------
def count_distinct_characters(string: str) -> int:
""" Given a string, find out how many distinct characters (regardless of case) does it consist of
>>> count_distinct_characters('xyzXYZ')
3
>>> count_distinct_characters('Jerry')
4
"""
--------CANONICAL SOLUTION--------
return len(set(string.lower()))
---------------------------------------INFO ABOUT TEST 16 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 17----------------------------------------
-------------PROMPT----------------
from typing import List
def parse_music(music_string: str) -> List[int]:
""" Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return list of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
>>> parse_music('o o| .| o| o| .| .| .| .| o o')
[4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
"""
--------CANONICAL SOLUTION--------
note_map = {'o': 4, 'o|': 2, '.|': 1}
return [note_map[x] for x in music_string.split(' ') if x]
---------------------------------------INFO ABOUT TEST 17 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 18----------------------------------------
-------------PROMPT----------------
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
--------CANONICAL SOLUTION--------
times = 0
for i in range(len(string) - len(substring) + 1):
if string[i:i+len(substring)] == substring:
times += 1
return times
---------------------------------------INFO ABOUT TEST 18 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 19----------------------------------------
-------------PROMPT----------------
from typing import List
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
>>> sort_numbers('three one five')
'one three five'
"""
--------CANONICAL SOLUTION--------
value_map = {
'zero': 0,
'one': 1,
'two': 2,
'three': 3,
'four': 4,
'five': 5,
'six': 6,
'seven': 7,
'eight': 8,
'nine': 9
}
return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
---------------------------------------INFO ABOUT TEST 19 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 20----------------------------------------
-------------PROMPT----------------
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
(2.0, 2.2)
>>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
(2.0, 2.0)
"""
--------CANONICAL SOLUTION--------
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
---------------------------------------INFO ABOUT TEST 20 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 21----------------------------------------
-------------PROMPT----------------
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, 0.25, 0.5, 0.75, 1.0]
"""
--------CANONICAL SOLUTION--------
min_number = min(numbers)
max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
---------------------------------------INFO ABOUT TEST 21 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 22----------------------------------------
-------------PROMPT----------------
from typing import List, Any
def filter_integers(values: List[Any]) -> List[int]:
""" Filter given list of any python values only for integers
>>> filter_integers(['a', 3.14, 5])
[5]
>>> filter_integers([1, 2, 3, 'abc', {}, []])
[1, 2, 3]
"""
--------CANONICAL SOLUTION--------
return [x for x in values if isinstance(x, int)]
---------------------------------------INFO ABOUT TEST 22 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 23----------------------------------------
-------------PROMPT----------------
def strlen(string: str) -> int:
""" Return length of given string
>>> strlen('')
0
>>> strlen('abc')
3
"""
--------CANONICAL SOLUTION--------
return len(string)
---------------------------------------INFO ABOUT TEST 23 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 24----------------------------------------
-------------PROMPT----------------
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
--------CANONICAL SOLUTION--------
for i in reversed(range(n)):
if n % i == 0:
return i
---------------------------------------INFO ABOUT TEST 24 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 25----------------------------------------
-------------PROMPT----------------
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
>>> factorize(8)
[2, 2, 2]
>>> factorize(25)
[5, 5]
>>> factorize(70)
[2, 5, 7]
"""
--------CANONICAL SOLUTION--------
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
---------------------------------------INFO ABOUT TEST 25 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 26----------------------------------------
-------------PROMPT----------------
from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
--------CANONICAL SOLUTION--------
import collections
c = collections.Counter(numbers)
return [n for n in numbers if c[n] <= 1]
---------------------------------------INFO ABOUT TEST 26 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 27----------------------------------------
-------------PROMPT----------------
def flip_case(string: str) -> str:
""" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
>>> flip_case('Hello')
'hELLO'
"""
--------CANONICAL SOLUTION--------
return string.swapcase()
---------------------------------------INFO ABOUT TEST 27 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 28----------------------------------------
-------------PROMPT----------------
from typing import List
def concatenate(strings: List[str]) -> str:
""" Concatenate list of strings into a single string
>>> concatenate([])
''
>>> concatenate(['a', 'b', 'c'])
'abc'
"""
--------CANONICAL SOLUTION--------
return ''.join(strings)
---------------------------------------INFO ABOUT TEST 28 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 29----------------------------------------
-------------PROMPT----------------
from typing import List
def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
""" Filter an input list of strings only for ones that start with a given prefix.
>>> filter_by_prefix([], 'a')
[]
>>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
['abc', 'array']
"""
--------CANONICAL SOLUTION--------
return [x for x in strings if x.startswith(prefix)]
---------------------------------------INFO ABOUT TEST 29 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 30----------------------------------------
-------------PROMPT----------------
def get_positive(l: list):
"""Return only positive numbers in the list.
>>> get_positive([-1, 2, -4, 5, 6])
[2, 5, 6]
>>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
[5, 3, 2, 3, 9, 123, 1]
"""
--------CANONICAL SOLUTION--------
return [e for e in l if e > 0]
---------------------------------------INFO ABOUT TEST 30 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 31----------------------------------------
-------------PROMPT----------------
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
--------CANONICAL SOLUTION--------
if n < 2:
return False
for k in range(2, n - 1):
if n % k == 0:
return False
return True
---------------------------------------INFO ABOUT TEST 31 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 32----------------------------------------
-------------PROMPT----------------
import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomial.
find_zero find x such that poly(x) = 0.
find_zero returns only only zero point, even if there are many.
Moreover, find_zero only takes list xs having even number of coefficients
and largest non zero coefficient as it guarantees
a solution.
>>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
-0.5
>>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
1.0
"""
--------CANONICAL SOLUTION--------
begin, end = -1., 1.
while poly(xs, begin) * poly(xs, end) > 0:
begin *= 2.0
end *= 2.0
while end - begin > 1e-10:
center = (begin + end) / 2.0
if poly(xs, center) * poly(xs, begin) > 0:
begin = center
else:
end = center
return begin
---------------------------------------INFO ABOUT TEST 32 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 33----------------------------------------
-------------PROMPT----------------
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_third([1, 2, 3])
[1, 2, 3]
>>> sort_third([5, 6, 3, 4, 8, 9, 2])
[2, 6, 3, 4, 8, 9, 5]
"""
--------CANONICAL SOLUTION--------
l = list(l)
l[::3] = sorted(l[::3])
return l
---------------------------------------INFO ABOUT TEST 33 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 34----------------------------------------
-------------PROMPT----------------
def unique(l: list):
"""Return sorted unique elements in a list
>>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
[0, 2, 3, 5, 9, 123]
"""
--------CANONICAL SOLUTION--------
return sorted(list(set(l)))
---------------------------------------INFO ABOUT TEST 34 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 35----------------------------------------
-------------PROMPT----------------
def max_element(l: list):
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
--------CANONICAL SOLUTION--------
m = l[0]
for e in l:
if e > m:
m = e
return m
---------------------------------------INFO ABOUT TEST 35 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 36----------------------------------------
-------------PROMPT----------------
def fizz_buzz(n: int):
"""Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
>>> fizz_buzz(50)
0
>>> fizz_buzz(78)
2
>>> fizz_buzz(79)
3
"""
--------CANONICAL SOLUTION--------
ns = []
for i in range(n):
if i % 11 == 0 or i % 13 == 0:
ns.append(i)
s = ''.join(list(map(str, ns)))
ans = 0
for c in s:
ans += (c == '7')
return ans
---------------------------------------INFO ABOUT TEST 36 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 37----------------------------------------
-------------PROMPT----------------
def sort_even(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[1, 2, 3]
>>> sort_even([5, 6, 3, 4])
[3, 6, 5, 4]
"""
--------CANONICAL SOLUTION--------
evens = l[::2]
odds = l[1::2]
evens.sort()
ans = []
for e, o in zip(evens, odds):
ans.extend([e, o])
if len(evens) > len(odds):
ans.append(evens[-1])
return ans
---------------------------------------INFO ABOUT TEST 37 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 38----------------------------------------
-------------PROMPT----------------
def encode_cyclic(s: str):
"""
returns encoded string by cycling groups of three characters.
"""
# split string to groups. Each of length 3.
groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
# cycle elements in each group. Unless group has fewer elements than 3.
groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
return "".join(groups)
def decode_cyclic(s: str):
"""
takes as input string encoded with encode_cyclic function. Returns decoded string.
"""
--------CANONICAL SOLUTION--------
return encode_cyclic(encode_cyclic(s))
---------------------------------------INFO ABOUT TEST 38 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 39----------------------------------------
-------------PROMPT----------------
def prime_fib(n: int):
"""
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
>>> prime_fib(1)
2
>>> prime_fib(2)
3
>>> prime_fib(3)
5
>>> prime_fib(4)
13
>>> prime_fib(5)
89
"""
--------CANONICAL SOLUTION--------
import math
def is_prime(p):
if p < 2:
return False
for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):
if p % k == 0:
return False
return True
f = [0, 1]
while True:
f.append(f[-1] + f[-2])
if is_prime(f[-1]):
n -= 1
if n == 0:
return f[-1]
---------------------------------------INFO ABOUT TEST 39 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 40----------------------------------------
-------------PROMPT----------------
def triples_sum_to_zero(l: list):
"""
triples_sum_to_zero takes a list of integers as an input.
it returns True if there are three distinct elements in the list that
sum to zero, and False otherwise.
>>> triples_sum_to_zero([1, 3, 5, 0])
False
>>> triples_sum_to_zero([1, 3, -2, 1])
True
>>> triples_sum_to_zero([1, 2, 3, 7])
False
>>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])
True
>>> triples_sum_to_zero([1])
False
"""
--------CANONICAL SOLUTION--------
for i in range(len(l)):
for j in range(i + 1, len(l)):
for k in range(j + 1, len(l)):
if l[i] + l[j] + l[k] == 0:
return True
return False
---------------------------------------INFO ABOUT TEST 40 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 41----------------------------------------
-------------PROMPT----------------
def car_race_collision(n: int):
"""
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
"""
--------CANONICAL SOLUTION--------
return n**2
---------------------------------------INFO ABOUT TEST 41 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 42----------------------------------------
-------------PROMPT----------------
def incr_list(l: list):
"""Return list with elements incremented by 1.
>>> incr_list([1, 2, 3])
[2, 3, 4]
>>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
[6, 4, 6, 3, 4, 4, 10, 1, 124]
"""
--------CANONICAL SOLUTION--------
return [(e + 1) for e in l]
---------------------------------------INFO ABOUT TEST 42 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 43----------------------------------------
-------------PROMPT----------------
def pairs_sum_to_zero(l):
"""
pairs_sum_to_zero takes a list of integers as an input.
it returns True if there are two distinct elements in the list that
sum to zero, and False otherwise.
>>> pairs_sum_to_zero([1, 3, 5, 0])
False
>>> pairs_sum_to_zero([1, 3, -2, 1])
False
>>> pairs_sum_to_zero([1, 2, 3, 7])
False
>>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])
True
>>> pairs_sum_to_zero([1])
False
"""
--------CANONICAL SOLUTION--------
for i, l1 in enumerate(l):
for j in range(i + 1, len(l)):
if l1 + l[j] == 0:
return True
return False
---------------------------------------INFO ABOUT TEST 43 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 44----------------------------------------
-------------PROMPT----------------
def change_base(x: int, base: int):
"""Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
>>> change_base(8, 3)
'22'
>>> change_base(8, 2)
'1000'
>>> change_base(7, 2)
'111'
"""
--------CANONICAL SOLUTION--------
ret = ""
while x > 0:
ret = str(x % base) + ret
x //= base
return ret
---------------------------------------INFO ABOUT TEST 44 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 45----------------------------------------
-------------PROMPT----------------
def triangle_area(a, h):
"""Given length of a side and high return area for a triangle.
>>> triangle_area(5, 3)
7.5
"""
--------CANONICAL SOLUTION--------
return a * h / 2.0
---------------------------------------INFO ABOUT TEST 45 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 46----------------------------------------
-------------PROMPT----------------
def fib4(n: int):
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
>>> fib4(5)
4
>>> fib4(6)
8
>>> fib4(7)
14
"""
--------CANONICAL SOLUTION--------
results = [0, 0, 2, 0]
if n < 4:
return results[n]
for _ in range(4, n + 1):
results.append(results[-1] + results[-2] + results[-3] + results[-4])
results.pop(0)
return results[-1]
---------------------------------------INFO ABOUT TEST 46 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 47----------------------------------------
-------------PROMPT----------------
def median(l: list):
"""Return median of elements in the list l.
>>> median([3, 1, 2, 4, 5])
3
>>> median([-10, 4, 6, 1000, 10, 20])
15.0
"""
--------CANONICAL SOLUTION--------
l = sorted(l)
if len(l) % 2 == 1:
return l[len(l) // 2]
else:
return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0
---------------------------------------INFO ABOUT TEST 47 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 48----------------------------------------
-------------PROMPT----------------
def is_palindrome(text: str):
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
--------CANONICAL SOLUTION--------
for i in range(len(text)):
if text[i] != text[len(text) - 1 - i]:
return False
return True
---------------------------------------INFO ABOUT TEST 48 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 49----------------------------------------
-------------PROMPT----------------
def modp(n: int, p: int):
"""Return 2^n modulo p (be aware of numerics).
>>> modp(3, 5)
3
>>> modp(1101, 101)
2
>>> modp(0, 101)
1
>>> modp(3, 11)
8
>>> modp(100, 101)
1
"""
--------CANONICAL SOLUTION--------
ret = 1
for i in range(n):
ret = (2 * ret) % p
return ret
---------------------------------------INFO ABOUT TEST 49 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 50----------------------------------------
-------------PROMPT----------------
def encode_shift(s: str):
"""
returns encoded string by shifting every character by 5 in the alphabet.
"""
return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])
def decode_shift(s: str):
"""
takes as input string encoded with encode_shift function. Returns decoded string.
"""
--------CANONICAL SOLUTION--------
return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
---------------------------------------INFO ABOUT TEST 50 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 51----------------------------------------
-------------PROMPT----------------
def remove_vowels(text):
"""
remove_vowels is a function that takes string and returns string without vowels.
>>> remove_vowels('')
''
>>> remove_vowels("abcdef\nghijklm")
'bcdf\nghjklm'
>>> remove_vowels('abcdef')
'bcdf'
>>> remove_vowels('aaaaa')
''
>>> remove_vowels('aaBAA')
'B'
>>> remove_vowels('zbcd')
'zbcd'
"""
--------CANONICAL SOLUTION--------
return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
---------------------------------------INFO ABOUT TEST 51 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 52----------------------------------------
-------------PROMPT----------------
def below_threshold(l: list, t: int):
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
--------CANONICAL SOLUTION--------
for e in l:
if e >= t:
return False
return True
---------------------------------------INFO ABOUT TEST 52 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 53----------------------------------------
-------------PROMPT----------------
def add(x: int, y: int):
"""Add two numbers x and y
>>> add(2, 3)
5
>>> add(5, 7)
12
"""
--------CANONICAL SOLUTION--------
return x + y
---------------------------------------INFO ABOUT TEST 53 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 54----------------------------------------
-------------PROMPT----------------
def same_chars(s0: str, s1: str):
"""
Check if two words have the same characters.
>>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
True
>>> same_chars('abcd', 'dddddddabc')
True
>>> same_chars('dddddddabc', 'abcd')
True
>>> same_chars('eabcd', 'dddddddabc')
False
>>> same_chars('abcd', 'dddddddabce')
False
>>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')
False
"""
--------CANONICAL SOLUTION--------
return set(s0) == set(s1)
---------------------------------------INFO ABOUT TEST 54 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 55----------------------------------------
-------------PROMPT----------------
def fib(n: int):
"""Return n-th Fibonacci number.
>>> fib(10)
55
>>> fib(1)
1
>>> fib(8)
21
"""
--------CANONICAL SOLUTION--------
if n == 0:
return 0
if n == 1:
return 1
return fib(n - 1) + fib(n - 2)
---------------------------------------INFO ABOUT TEST 55 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 56----------------------------------------
-------------PROMPT----------------
def correct_bracketing(brackets: str):
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("<")
False
>>> correct_bracketing("<>")
True
>>> correct_bracketing("<<><>>")
True
>>> correct_bracketing("><<>")
False
"""
--------CANONICAL SOLUTION--------
depth = 0
for b in brackets:
if b == "<":
depth += 1
else:
depth -= 1
if depth < 0:
return False
return depth == 0
---------------------------------------INFO ABOUT TEST 56 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 57----------------------------------------
-------------PROMPT----------------
def monotonic(l: list):
"""Return True is list elements are monotonically increasing or decreasing.
>>> monotonic([1, 2, 4, 20])
True
>>> monotonic([1, 20, 4, 10])
False
>>> monotonic([4, 1, 0, -10])
True
"""
--------CANONICAL SOLUTION--------
if l == sorted(l) or l == sorted(l, reverse=True):
return True
return False
---------------------------------------INFO ABOUT TEST 57 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 58----------------------------------------
-------------PROMPT----------------
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
--------CANONICAL SOLUTION--------
ret = set()
for e1 in l1:
for e2 in l2:
if e1 == e2:
ret.add(e1)
return sorted(list(ret))
---------------------------------------INFO ABOUT TEST 58 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 59----------------------------------------
-------------PROMPT----------------
def largest_prime_factor(n: int):
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
--------CANONICAL SOLUTION--------
def is_prime(k):
if k < 2:
return False
for i in range(2, k - 1):
if k % i == 0:
return False
return True
largest = 1
for j in range(2, n + 1):
if n % j == 0 and is_prime(j):
largest = max(largest, j)
return largest
---------------------------------------INFO ABOUT TEST 59 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 60----------------------------------------
-------------PROMPT----------------
def sum_to_n(n: int):
"""sum_to_n is a function that sums numbers from 1 to n.
>>> sum_to_n(30)
465
>>> sum_to_n(100)
5050
>>> sum_to_n(5)
15
>>> sum_to_n(10)
55
>>> sum_to_n(1)
1
"""
--------CANONICAL SOLUTION--------
return sum(range(n + 1))
---------------------------------------INFO ABOUT TEST 60 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 61----------------------------------------
-------------PROMPT----------------
def correct_bracketing(brackets: str):
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("(")
False
>>> correct_bracketing("()")
True
>>> correct_bracketing("(()())")
True
>>> correct_bracketing(")(()")
False
"""
--------CANONICAL SOLUTION--------
depth = 0
for b in brackets:
if b == "(":
depth += 1
else:
depth -= 1
if depth < 0:
return False
return depth == 0
---------------------------------------INFO ABOUT TEST 61 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 62----------------------------------------
-------------PROMPT----------------
def derivative(xs: list):
""" xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
>>> derivative([3, 1, 2, 4, 5])
[1, 4, 12, 20]
>>> derivative([1, 2, 3])
[2, 6]
"""
--------CANONICAL SOLUTION--------
return [(i * x) for i, x in enumerate(xs)][1:]
---------------------------------------INFO ABOUT TEST 62 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 63----------------------------------------
-------------PROMPT----------------
def fibfib(n: int):
"""The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
>>> fibfib(1)
0
>>> fibfib(5)
4
>>> fibfib(8)
24
"""
--------CANONICAL SOLUTION--------
if n == 0:
return 0
if n == 1:
return 0
if n == 2:
return 1
return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
---------------------------------------INFO ABOUT TEST 63 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 64----------------------------------------
-------------PROMPT----------------
FIX = """
Add more test cases.
"""
def vowels_count(s):
"""Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
>>> vowels_count("abcde")
2
>>> vowels_count("ACEDY")
3
"""
--------CANONICAL SOLUTION--------
vowels = "aeiouAEIOU"
n_vowels = sum(c in vowels for c in s)
if s[-1] == 'y' or s[-1] == 'Y':
n_vowels += 1
return n_vowels
---------------------------------------INFO ABOUT TEST 64 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 65----------------------------------------
-------------PROMPT----------------
def circular_shift(x, shift):
"""Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
>>> circular_shift(12, 1)
"21"
>>> circular_shift(12, 2)
"12"
"""
--------CANONICAL SOLUTION--------
s = str(x)
if shift > len(s):
return s[::-1]
else:
return s[len(s) - shift:] + s[:len(s) - shift]
---------------------------------------INFO ABOUT TEST 65 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 66----------------------------------------
-------------PROMPT----------------
def digitSum(s):
"""Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum("") => 0
digitSum("abAB") => 131
digitSum("abcCd") => 67
digitSum("helloE") => 69
digitSum("woArBld") => 131
digitSum("aAaaaXa") => 153
"""
--------CANONICAL SOLUTION--------
if s == "": return 0
return sum(ord(char) if char.isupper() else 0 for char in s)
---------------------------------------INFO ABOUT TEST 66 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 67----------------------------------------
-------------PROMPT----------------
def fruit_distribution(s,n):
"""
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8
fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2
fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95
fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19
"""
--------CANONICAL SOLUTION--------
lis = list()
for i in s.split(' '):
if i.isdigit():
lis.append(int(i))
return n - sum(lis)
---------------------------------------INFO ABOUT TEST 67 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 68----------------------------------------
-------------PROMPT----------------
def pluck(arr):
"""
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in a list, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Input: [4,2,3]
Output: [2, 1]
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Input: [1,2,3]
Output: [2, 1]
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Input: []
Output: []
Example 4:
Input: [5, 0, 3, 0, 4, 2]
Output: [0, 1]
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
"""
--------CANONICAL SOLUTION--------
if(len(arr) == 0): return []
evens = list(filter(lambda x: x%2 == 0, arr))
if(evens == []): return []
return [min(evens), arr.index(min(evens))]
---------------------------------------INFO ABOUT TEST 68 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 69----------------------------------------
-------------PROMPT----------------
def search(lst):
'''
You are given a non-empty list of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the list.
If no such a value exist, return -1.
Examples:
search([4, 1, 2, 2, 3, 1]) == 2
search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search([5, 5, 4, 4, 4]) == -1
'''
--------CANONICAL SOLUTION--------
frq = [0] * (max(lst) + 1)
for i in lst:
frq[i] += 1;
ans = -1
for i in range(1, len(frq)):
if frq[i] >= i:
ans = i
return ans
---------------------------------------INFO ABOUT TEST 69 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 70----------------------------------------
-------------PROMPT----------------
def strange_sort_list(lst):
'''
Given list of integers, return list in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]
strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]
strange_sort_list([]) == []
'''
--------CANONICAL SOLUTION--------
res, switch = [], True
while lst:
res.append(min(lst) if switch else max(lst))
lst.remove(res[-1])
switch = not switch
return res
---------------------------------------INFO ABOUT TEST 70 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 71----------------------------------------
-------------PROMPT----------------
def triangle_area(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangle_area(3, 4, 5) == 6.00
triangle_area(1, 2, 10) == -1
'''
--------CANONICAL SOLUTION--------
if a + b <= c or a + c <= b or b + c <= a:
return -1
s = (a + b + c)/2
area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
area = round(area, 2)
return area
---------------------------------------INFO ABOUT TEST 71 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 72----------------------------------------
-------------PROMPT----------------
def will_it_fly(q,w):
'''
Write a function that returns True if the object q will fly, and False otherwise.
The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
will_it_fly([1, 2], 5) ➞ False
# 1+2 is less than the maximum possible weight, but it's unbalanced.
will_it_fly([3, 2, 3], 1) ➞ False
# it's balanced, but 3+2+3 is more than the maximum possible weight.
will_it_fly([3, 2, 3], 9) ➞ True
# 3+2+3 is less than the maximum possible weight, and it's balanced.
will_it_fly([3], 5) ➞ True
# 3 is less than the maximum possible weight, and it's balanced.
'''
--------CANONICAL SOLUTION--------
if sum(q) > w:
return False
i, j = 0, len(q)-1
while i<j:
if q[i] != q[j]:
return False
i+=1
j-=1
return True
---------------------------------------INFO ABOUT TEST 72 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 73----------------------------------------
-------------PROMPT----------------
def smallest_change(arr):
"""
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallest_change([1,2,3,5,4,7,9,6]) == 4
smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
smallest_change([1, 2, 3, 2, 1]) == 0
"""
--------CANONICAL SOLUTION--------
ans = 0
for i in range(len(arr) // 2):
if arr[i] != arr[len(arr) - i - 1]:
ans += 1
return ans
---------------------------------------INFO ABOUT TEST 73 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 74----------------------------------------
-------------PROMPT----------------
def total_match(lst1, lst2):
'''
Write a function that accepts two lists of strings and returns the list that has
total number of chars in the all strings of the list less than the other list.
if the two lists have the same number of chars, return the first list.
Examples
total_match([], []) ➞ []
total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
'''
--------CANONICAL SOLUTION--------
l1 = 0
for st in lst1:
l1 += len(st)
l2 = 0
for st in lst2:
l2 += len(st)
if l1 <= l2:
return lst1
else:
return lst2
---------------------------------------INFO ABOUT TEST 74 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 75----------------------------------------
-------------PROMPT----------------
def is_multiply_prime(a):
"""Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
is_multiply_prime(30) == True
30 = 2 * 3 * 5
"""
--------CANONICAL SOLUTION--------
def is_prime(n):
for j in range(2,n):
if n%j == 0:
return False
return True
for i in range(2,101):
if not is_prime(i): continue
for j in range(2,101):
if not is_prime(j): continue
for k in range(2,101):
if not is_prime(k): continue
if i*j*k == a: return True
return False
---------------------------------------INFO ABOUT TEST 75 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 76----------------------------------------
-------------PROMPT----------------
def is_simple_power(x, n):
"""Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
is_simple_power(1, 4) => true
is_simple_power(2, 2) => true
is_simple_power(8, 2) => true
is_simple_power(3, 2) => false
is_simple_power(3, 1) => false
is_simple_power(5, 3) => false
"""
--------CANONICAL SOLUTION--------
if (n == 1):
return (x == 1)
power = 1
while (power < x):
power = power * n
return (power == x)
---------------------------------------INFO ABOUT TEST 76 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 77----------------------------------------
-------------PROMPT----------------
def iscube(a):
'''
Write a function that takes an integer a and returns True
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(1) ==> True
iscube(2) ==> False
iscube(-1) ==> True
iscube(64) ==> True
iscube(0) ==> True
iscube(180) ==> False
'''
--------CANONICAL SOLUTION--------
a = abs(a)
return int(round(a ** (1. / 3))) ** 3 == a
---------------------------------------INFO ABOUT TEST 77 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 78----------------------------------------
-------------PROMPT----------------
def hex_key(num):
"""You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
For num = "AB" the output should be 1.
For num = "1077E" the output should be 2.
For num = "ABED1A33" the output should be 4.
For num = "123456789ABCDEF0" the output should be 6.
For num = "2020" the output should be 2.
"""
--------CANONICAL SOLUTION--------
primes = ('2', '3', '5', '7', 'B', 'D')
total = 0
for i in range(0, len(num)):
if num[i] in primes:
total += 1
return total
---------------------------------------INFO ABOUT TEST 78 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 79----------------------------------------
-------------PROMPT----------------
def decimal_to_binary(decimal):
"""You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimal_to_binary(15) # returns "db1111db"
decimal_to_binary(32) # returns "db100000db"
"""
--------CANONICAL SOLUTION--------
return "db" + bin(decimal)[2:] + "db"
---------------------------------------INFO ABOUT TEST 79 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 80----------------------------------------
-------------PROMPT----------------
def is_happy(s):
"""You are given a string s.
Your task is to check if the string is happy or not.
A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
For example:
is_happy(a) => False
is_happy(aa) => False
is_happy(abcd) => True
is_happy(aabb) => False
is_happy(adb) => True
is_happy(xyy) => False
"""
--------CANONICAL SOLUTION--------
if len(s) < 3:
return False
for i in range(len(s) - 2):
if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
return False
return True
---------------------------------------INFO ABOUT TEST 80 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 81----------------------------------------
-------------PROMPT----------------
def numerical_letter_grade(grades):
"""It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you a list of GPAs for some students and you have to write
a function that can output a list of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
"""
--------CANONICAL SOLUTION--------
letter_grade = []
for gpa in grades:
if gpa == 4.0:
letter_grade.append("A+")
elif gpa > 3.7:
letter_grade.append("A")
elif gpa > 3.3:
letter_grade.append("A-")
elif gpa > 3.0:
letter_grade.append("B+")
elif gpa > 2.7:
letter_grade.append("B")
elif gpa > 2.3:
letter_grade.append("B-")
elif gpa > 2.0:
letter_grade.append("C+")
elif gpa > 1.7:
letter_grade.append("C")
elif gpa > 1.3:
letter_grade.append("C-")
elif gpa > 1.0:
letter_grade.append("D+")
elif gpa > 0.7:
letter_grade.append("D")
elif gpa > 0.0:
letter_grade.append("D-")
else:
letter_grade.append("E")
return letter_grade
---------------------------------------INFO ABOUT TEST 81 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 82----------------------------------------
-------------PROMPT----------------
def prime_length(string):
"""Write a function that takes a string and returns True if the string
length is a prime number or False otherwise
Examples
prime_length('Hello') == True
prime_length('abcdcba') == True
prime_length('kittens') == True
prime_length('orange') == False
"""
--------CANONICAL SOLUTION--------
l = len(string)
if l == 0 or l == 1:
return False
for i in range(2, l):
if l % i == 0:
return False
return True
---------------------------------------INFO ABOUT TEST 82 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 83----------------------------------------
-------------PROMPT----------------
def starts_one_ends(n):
"""
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
"""
--------CANONICAL SOLUTION--------
if n == 1: return 1
return 18 * (10 ** (n - 2))
---------------------------------------INFO ABOUT TEST 83 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 84----------------------------------------
-------------PROMPT----------------
def solve(N):
"""Given a positive integer N, return the total sum of its digits in binary.
Example
For N = 1000, the sum of digits will be 1 the output should be "1".
For N = 150, the sum of digits will be 6 the output should be "110".
For N = 147, the sum of digits will be 12 the output should be "1100".
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
"""
--------CANONICAL SOLUTION--------
return bin(sum(int(i) for i in str(N)))[2:]
---------------------------------------INFO ABOUT TEST 84 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 85----------------------------------------
-------------PROMPT----------------
def add(lst):
"""Given a non-empty list of integers lst. add the even elements that are at odd indices..
Examples:
add([4, 2, 6, 7]) ==> 2
"""
--------CANONICAL SOLUTION--------
return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])
---------------------------------------INFO ABOUT TEST 85 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 86----------------------------------------
-------------PROMPT----------------
def anti_shuffle(s):
"""
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
anti_shuffle('Hi') returns 'Hi'
anti_shuffle('hello') returns 'ehllo'
anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'
"""
--------CANONICAL SOLUTION--------
return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])
---------------------------------------INFO ABOUT TEST 86 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 87----------------------------------------
-------------PROMPT----------------
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
--------CANONICAL SOLUTION--------
coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]
return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
---------------------------------------INFO ABOUT TEST 87 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 88----------------------------------------
-------------PROMPT----------------
def sort_array(array):
"""
Given an array of non-negative integers, return a copy of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
* sort_array([]) => []
* sort_array([5]) => [5]
* sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]
* sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]
"""
--------CANONICAL SOLUTION--------
return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)
---------------------------------------INFO ABOUT TEST 88 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 89----------------------------------------
-------------PROMPT----------------
def encrypt(s):
"""Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt('hi') returns 'lm'
encrypt('asdfghjkl') returns 'ewhjklnop'
encrypt('gf') returns 'kj'
encrypt('et') returns 'ix'
"""
--------CANONICAL SOLUTION--------
d = 'abcdefghijklmnopqrstuvwxyz'
out = ''
for c in s:
if c in d:
out += d[(d.index(c)+2*2) % 26]
else:
out += c
return out
---------------------------------------INFO ABOUT TEST 89 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 90----------------------------------------
-------------PROMPT----------------
def next_smallest(lst):
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
next_smallest([1, 2, 3, 4, 5]) == 2
next_smallest([5, 1, 4, 3, 2]) == 2
next_smallest([]) == None
next_smallest([1, 1]) == None
"""
--------CANONICAL SOLUTION--------
lst = sorted(set(lst))
return None if len(lst) < 2 else lst[1]
---------------------------------------INFO ABOUT TEST 90 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 91----------------------------------------
-------------PROMPT----------------
def is_bored(S):
"""
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
>>> is_bored("Hello world")
0
>>> is_bored("The sky is blue. The sun is shining. I love this weather")
1
"""
--------CANONICAL SOLUTION--------
import re
sentences = re.split(r'[.?!]\s*', S)
return sum(sentence[0:2] == 'I ' for sentence in sentences)
---------------------------------------INFO ABOUT TEST 91 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 92----------------------------------------
-------------PROMPT----------------
def any_int(x, y, z):
'''
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
any_int(5, 2, 7) ➞ True
any_int(3, 2, 2) ➞ False
any_int(3, -2, 1) ➞ True
any_int(3.6, -2.2, 2) ➞ False
'''
--------CANONICAL SOLUTION--------
if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):
if (x+y==z) or (x+z==y) or (y+z==x):
return True
return False
return False
---------------------------------------INFO ABOUT TEST 92 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 93----------------------------------------
-------------PROMPT----------------
def encode(message):
"""
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
>>> encode('test')
'TGST'
>>> encode('This is a message')
'tHKS KS C MGSSCGG'
"""
--------CANONICAL SOLUTION--------
vowels = "aeiouAEIOU"
vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])
message = message.swapcase()
return ''.join([vowels_replace[i] if i in vowels else i for i in message])
---------------------------------------INFO ABOUT TEST 93 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 94----------------------------------------
-------------PROMPT----------------
def skjkasdkd(lst):
"""You are given a list of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10
For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25
For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13
For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11
For lst = [0,81,12,3,1,21] the output should be 3
For lst = [0,8,1,2,1,7] the output should be 7
"""
--------CANONICAL SOLUTION--------
def isPrime(n):
for i in range(2,int(n**0.5)+1):
if n%i==0:
return False
return True
maxx = 0
i = 0
while i < len(lst):
if(lst[i] > maxx and isPrime(lst[i])):
maxx = lst[i]
i+=1
result = sum(int(digit) for digit in str(maxx))
return result
---------------------------------------INFO ABOUT TEST 94 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 95----------------------------------------
-------------PROMPT----------------
def check_dict_case(dict):
"""
Given a dictionary, return True if all keys are strings in lower
case or all keys are strings in upper case, else return False.
The function should return False is the given dictionary is empty.
Examples:
check_dict_case({"a":"apple", "b":"banana"}) should return True.
check_dict_case({"a":"apple", "A":"banana", "B":"banana"}) should return False.
check_dict_case({"a":"apple", 8:"banana", "a":"apple"}) should return False.
check_dict_case({"Name":"John", "Age":"36", "City":"Houston"}) should return False.
check_dict_case({"STATE":"NC", "ZIP":"12345" }) should return True.
"""
--------CANONICAL SOLUTION--------
if len(dict.keys()) == 0:
return False
else:
state = "start"
for key in dict.keys():
if isinstance(key, str) == False:
state = "mixed"
break
if state == "start":
if key.isupper():
state = "upper"
elif key.islower():
state = "lower"
else:
break
elif (state == "upper" and not key.isupper()) or (state == "lower" and not key.islower()):
state = "mixed"
break
else:
break
return state == "upper" or state == "lower"
---------------------------------------INFO ABOUT TEST 95 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 96----------------------------------------
-------------PROMPT----------------
def count_up_to(n):
"""Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
count_up_to(5) => [2,3]
count_up_to(11) => [2,3,5,7]
count_up_to(0) => []
count_up_to(20) => [2,3,5,7,11,13,17,19]
count_up_to(1) => []
count_up_to(18) => [2,3,5,7,11,13,17]
"""
--------CANONICAL SOLUTION--------
primes = []
for i in range(2, n):
is_prime = True
for j in range(2, i):
if i % j == 0:
is_prime = False
break
if is_prime:
primes.append(i)
return primes
---------------------------------------INFO ABOUT TEST 96 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 97----------------------------------------
-------------PROMPT----------------
def multiply(a, b):
"""Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(148, 412) should return 16.
multiply(19, 28) should return 72.
multiply(2020, 1851) should return 0.
multiply(14,-15) should return 20.
"""
--------CANONICAL SOLUTION--------
return abs(a % 10) * abs(b % 10)
---------------------------------------INFO ABOUT TEST 97 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 98----------------------------------------
-------------PROMPT----------------
def count_upper(s):
"""
Given a string s, count the number of uppercase vowels in even indices.
For example:
count_upper('aBCdEf') returns 1
count_upper('abcdefg') returns 0
count_upper('dBBE') returns 0
"""
--------CANONICAL SOLUTION--------
count = 0
for i in range(0,len(s),2):
if s[i] in "AEIOU":
count += 1
return count
---------------------------------------INFO ABOUT TEST 98 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 99----------------------------------------
-------------PROMPT----------------
def closest_integer(value):
'''
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
>>> closest_integer("10")
10
>>> closest_integer("15.3")
15
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
'''
--------CANONICAL SOLUTION--------
from math import floor, ceil
if value.count('.') == 1:
# remove trailing zeros
while (value[-1] == '0'):
value = value[:-1]
num = float(value)
if value[-2:] == '.5':
if num > 0:
res = ceil(num)
else:
res = floor(num)
elif len(value) > 0:
res = int(round(num))
else:
res = 0
return res
---------------------------------------INFO ABOUT TEST 99 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 100----------------------------------------
-------------PROMPT----------------
def make_a_pile(n):
"""
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in a list, where element at index
i represents the number of stones in the level (i+1).
Examples:
>>> make_a_pile(3)
[3, 5, 7]
"""
--------CANONICAL SOLUTION--------
return [n + 2*i for i in range(n)]
---------------------------------------INFO ABOUT TEST 100 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 101----------------------------------------
-------------PROMPT----------------
def words_string(s):
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
"""
--------CANONICAL SOLUTION--------
if not s:
return []
s_list = []
for letter in s:
if letter == ',':
s_list.append(' ')
else:
s_list.append(letter)
s_list = "".join(s_list)
return s_list.split()
---------------------------------------INFO ABOUT TEST 101 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 102----------------------------------------
-------------PROMPT----------------
def choose_num(x, y):
"""This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
choose_num(12, 15) = 14
choose_num(13, 12) = -1
"""
--------CANONICAL SOLUTION--------
if x > y:
return -1
if y % 2 == 0:
return y
if x == y:
return -1
return y - 1
---------------------------------------INFO ABOUT TEST 102 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 103----------------------------------------
-------------PROMPT----------------
def rounded_avg(n, m):
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5) => "0b11"
rounded_avg(7, 5) => -1
rounded_avg(10, 20) => "0b1111"
rounded_avg(20, 33) => "0b11010"
"""
--------CANONICAL SOLUTION--------
if m < n:
return -1
summation = 0
for i in range(n, m+1):
summation += i
return bin(round(summation/(m - n + 1)))
---------------------------------------INFO ABOUT TEST 103 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 104----------------------------------------
-------------PROMPT----------------
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
--------CANONICAL SOLUTION--------
odd_digit_elements = []
for i in x:
if all (int(c) % 2 == 1 for c in str(i)):
odd_digit_elements.append(i)
return sorted(odd_digit_elements)
---------------------------------------INFO ABOUT TEST 104 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 105----------------------------------------
-------------PROMPT----------------
def by_length(arr):
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
arr = [2, 1, 1, 4, 5, 8, 2, 3]
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8]
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
If the array is empty, return an empty array:
arr = []
return []
If the array has any strange number ignore it:
arr = [1, -1 , 55]
-> sort arr -> [-1, 1, 55]
-> reverse arr -> [55, 1, -1]
return = ['One']
"""
--------CANONICAL SOLUTION--------
dic = {
1: "One",
2: "Two",
3: "Three",
4: "Four",
5: "Five",
6: "Six",
7: "Seven",
8: "Eight",
9: "Nine",
}
sorted_arr = sorted(arr, reverse=True)
new_arr = []
for var in sorted_arr:
try:
new_arr.append(dic[var])
except:
pass
return new_arr
---------------------------------------INFO ABOUT TEST 105 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 106----------------------------------------
-------------PROMPT----------------
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(5) == [1, 2, 6, 24, 15]
"""
--------CANONICAL SOLUTION--------
ret = []
for i in range(1,n+1):
if i%2 == 0:
x = 1
for j in range(1,i+1): x *= j
ret += [x]
else:
x = 0
for j in range(1,i+1): x += j
ret += [x]
return ret
---------------------------------------INFO ABOUT TEST 106 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 107----------------------------------------
-------------PROMPT----------------
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Input: 12
Output: (4, 6)
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
"""
--------CANONICAL SOLUTION--------
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
---------------------------------------INFO ABOUT TEST 107 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 108----------------------------------------
-------------PROMPT----------------
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
>>> count_nums([]) == 0
>>> count_nums([-1, 11, -11]) == 1
>>> count_nums([1, 1, 2]) == 3
"""
--------CANONICAL SOLUTION--------
def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
---------------------------------------INFO ABOUT TEST 108 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 109----------------------------------------
-------------PROMPT----------------
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
For Example:
move_one_ball([3, 4, 5, 1, 2])==>True
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
move_one_ball([3, 5, 4, 1, 2])==>False
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
"""
--------CANONICAL SOLUTION--------
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
---------------------------------------INFO ABOUT TEST 109 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 110----------------------------------------
-------------PROMPT----------------
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
It is assumed that the input lists will be non-empty.
"""
--------CANONICAL SOLUTION--------
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
---------------------------------------INFO ABOUT TEST 110 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 111----------------------------------------
-------------PROMPT----------------
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
histogram('a b b a') == {'a': 2, 'b': 2}
histogram('a b c a b') == {'a': 2, 'b': 2}
histogram('b b b b a') == {'b': 4}
histogram('') == {}
"""
--------CANONICAL SOLUTION--------
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
---------------------------------------INFO ABOUT TEST 111 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 112----------------------------------------
-------------PROMPT----------------
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and True/False for the check.
Example
For s = "abcde", c = "ae", the result should be ('bcd',False)
For s = "abcdef", c = "b" the result should be ('acdef',False)
For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
"""
--------CANONICAL SOLUTION--------
s = ''.join([char for char in s if char not in c])
return (s,s[::-1] == s)
---------------------------------------INFO ABOUT TEST 112 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 113----------------------------------------
-------------PROMPT----------------
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
>>> odd_count(['1234567'])
["the number of odd elements 4n the str4ng 4 of the 4nput."]
>>> odd_count(['3',"11111111"])
["the number of odd elements 1n the str1ng 1 of the 1nput.",
"the number of odd elements 8n the str8ng 8 of the 8nput."]
"""
--------CANONICAL SOLUTION--------
res = []
for arr in lst:
n = sum(int(d)%2==1 for d in arr)
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
return res
---------------------------------------INFO ABOUT TEST 113 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 114----------------------------------------
-------------PROMPT----------------
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6
"""
--------CANONICAL SOLUTION--------
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
---------------------------------------INFO ABOUT TEST 114 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 115----------------------------------------
-------------PROMPT----------------
def max_fill(grid, capacity):
import math
"""
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Input:
grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
bucket_capacity : 1
Output: 6
Example 2:
Input:
grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
bucket_capacity : 2
Output: 5
Example 3:
Input:
grid : [[0,0,0], [0,0,0]]
bucket_capacity : 5
Output: 0
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
"""
--------CANONICAL SOLUTION--------
return sum([math.ceil(sum(arr)/capacity) for arr in grid])
---------------------------------------INFO ABOUT TEST 115 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 116----------------------------------------
-------------PROMPT----------------
def sort_array(arr):
"""
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
>>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
>>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
>>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
"""
--------CANONICAL SOLUTION--------
return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
---------------------------------------INFO ABOUT TEST 116 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 117----------------------------------------
-------------PROMPT----------------
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
Examples:
select_words("Mary had a little lamb", 4) ==> ["little"]
select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
select_words("simple white space", 2) ==> []
select_words("Hello world", 4) ==> ["world"]
select_words("Uncle sam", 3) ==> ["Uncle"]
"""
--------CANONICAL SOLUTION--------
result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
---------------------------------------INFO ABOUT TEST 117 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 118----------------------------------------
-------------PROMPT----------------
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
get_closest_vowel("yogurt") ==> "u"
get_closest_vowel("FULL") ==> "U"
get_closest_vowel("quick") ==> ""
get_closest_vowel("ab") ==> ""
"""
--------CANONICAL SOLUTION--------
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
---------------------------------------INFO ABOUT TEST 118 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 119----------------------------------------
-------------PROMPT----------------
def match_parens(lst):
'''
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
match_parens(['()(', ')']) == 'Yes'
match_parens([')', ')']) == 'No'
'''
--------CANONICAL SOLUTION--------
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
---------------------------------------INFO ABOUT TEST 119 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 120----------------------------------------
-------------PROMPT----------------
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
Input: arr = [-3, -4, 5], k = 3
Output: [-4, -3, 5]
Example 2:
Input: arr = [4, -4, 4], k = 2
Output: [4, 4]
Example 3:
Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
Output: [2]
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
"""
--------CANONICAL SOLUTION--------
if k == 0:
return []
arr.sort()
ans = arr[-k:]
return ans
---------------------------------------INFO ABOUT TEST 120 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 121----------------------------------------
-------------PROMPT----------------
def solution(lst):
"""Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution([5, 8, 7, 1]) ==> 12
solution([3, 3, 3, 3, 3]) ==> 9
solution([30, 13, 24, 321]) ==>0
"""
--------CANONICAL SOLUTION--------
return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
---------------------------------------INFO ABOUT TEST 121 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 122----------------------------------------
-------------PROMPT----------------
def add_elements(arr, k):
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
Output: 24 # sum of 21 + 3
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
"""
--------CANONICAL SOLUTION--------
return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
---------------------------------------INFO ABOUT TEST 122 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 123----------------------------------------
-------------PROMPT----------------
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
"""
--------CANONICAL SOLUTION--------
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
---------------------------------------INFO ABOUT TEST 123 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 124----------------------------------------
-------------PROMPT----------------
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
for example:
valid_date('03-11-2000') => True
valid_date('15-01-2012') => False
valid_date('04-0-2040') => False
valid_date('06-04-2020') => True
valid_date('06/04/2020') => False
"""
--------CANONICAL SOLUTION--------
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
---------------------------------------INFO ABOUT TEST 124 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 125----------------------------------------
-------------PROMPT----------------
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
split_words("Hello world!") ➞ ["Hello", "world!"]
split_words("Hello,world!") ➞ ["Hello", "world!"]
split_words("abcdef") == 3
'''
--------CANONICAL SOLUTION--------
if " " in txt:
return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
---------------------------------------INFO ABOUT TEST 125 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 126----------------------------------------
-------------PROMPT----------------
def is_sorted(lst):
'''
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
Examples
is_sorted([5]) ➞ True
is_sorted([1, 2, 3, 4, 5]) ➞ True
is_sorted([1, 3, 2, 4, 5]) ➞ False
is_sorted([1, 2, 3, 4, 5, 6]) ➞ True
is_sorted([1, 2, 3, 4, 5, 6, 7]) ➞ True
is_sorted([1, 3, 2, 4, 5, 6, 7]) ➞ False
is_sorted([1, 2, 2, 3, 3, 4]) ➞ True
is_sorted([1, 2, 2, 2, 3, 4]) ➞ False
'''
--------CANONICAL SOLUTION--------
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
---------------------------------------INFO ABOUT TEST 126 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 127----------------------------------------
-------------PROMPT----------------
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection((1, 2), (2, 3)) ==> "NO"
intersection((-1, 1), (0, 4)) ==> "NO"
intersection((-3, -1), (-5, 5)) ==> "YES"
"""
--------CANONICAL SOLUTION--------
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
---------------------------------------INFO ABOUT TEST 127 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 128----------------------------------------
-------------PROMPT----------------
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
Example:
>>> prod_signs([1, 2, 2, -4]) == -9
>>> prod_signs([0, 1]) == 0
>>> prod_signs([]) == None
"""
--------CANONICAL SOLUTION--------
if not arr: return None
prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
return prod * sum([abs(i) for i in arr])
---------------------------------------INFO ABOUT TEST 128 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 129----------------------------------------
-------------PROMPT----------------
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
Examples:
Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3
Output: [1, 2, 1]
Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1
Output: [1]
"""
--------CANONICAL SOLUTION--------
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
---------------------------------------INFO ABOUT TEST 129 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 130----------------------------------------
-------------PROMPT----------------
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return a list of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(3) = [1, 3, 2, 8]
"""
--------CANONICAL SOLUTION--------
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
---------------------------------------INFO ABOUT TEST 130 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 131----------------------------------------
-------------PROMPT----------------
def digits(n):
"""Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15
"""
--------CANONICAL SOLUTION--------
product = 1
odd_count = 0
for digit in str(n):
int_digit = int(digit)
if int_digit%2 == 1:
product= product*int_digit
odd_count+=1
if odd_count ==0:
return 0
else:
return product
---------------------------------------INFO ABOUT TEST 131 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 132----------------------------------------
-------------PROMPT----------------
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[]]]]]]][[[[[]') ➞ False
is_nested('[][]') ➞ False
is_nested('[]') ➞ False
is_nested('[[][]]') ➞ True
is_nested('[[]][[') ➞ True
'''
--------CANONICAL SOLUTION--------
opening_bracket_index = []
closing_bracket_index = []
for i in range(len(string)):
if string[i] == '[':
opening_bracket_index.append(i)
else:
closing_bracket_index.append(i)
closing_bracket_index.reverse()
cnt = 0
i = 0
l = len(closing_bracket_index)
for idx in opening_bracket_index:
if i < l and idx < closing_bracket_index[i]:
cnt += 1
i += 1
return cnt >= 2
---------------------------------------INFO ABOUT TEST 132 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 133----------------------------------------
-------------PROMPT----------------
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst = [1,3,5,7] the output should be 84
For lst = [1.4,4.2,0] the output should be 29
For lst = [-2.4,1,1] the output should be 6
"""
--------CANONICAL SOLUTION--------
import math
squared = 0
for i in lst:
squared += math.ceil(i)**2
return squared
---------------------------------------INFO ABOUT TEST 133 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 134----------------------------------------
-------------PROMPT----------------
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_a_letter("apple pie") ➞ False
check_if_last_char_is_a_letter("apple pi e") ➞ True
check_if_last_char_is_a_letter("apple pi e ") ➞ False
check_if_last_char_is_a_letter("") ➞ False
'''
--------CANONICAL SOLUTION--------
check = txt.split(' ')[-1]
return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
---------------------------------------INFO ABOUT TEST 134 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 135----------------------------------------
-------------PROMPT----------------
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) = 3
can_arrange([1,2,3]) = -1
"""
--------CANONICAL SOLUTION--------
ind=-1
i=1
while i<len(arr):
if arr[i]<arr[i-1]:
ind=i
i+=1
return ind
---------------------------------------INFO ABOUT TEST 135 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 136----------------------------------------
-------------PROMPT----------------
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)
largest_smallest_integers([]) == (None, None)
largest_smallest_integers([0]) == (None, None)
'''
--------CANONICAL SOLUTION--------
smallest = list(filter(lambda x: x < 0, lst))
largest = list(filter(lambda x: x > 0, lst))
return (max(smallest) if smallest else None, min(largest) if largest else None)
---------------------------------------INFO ABOUT TEST 136 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 137----------------------------------------
-------------PROMPT----------------
def compare_one(a, b):
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compare_one(1, 2.5) ➞ 2.5
compare_one(1, "2,3") ➞ "2,3"
compare_one("5,1", "6") ➞ "6"
compare_one("1", 1) ➞ None
"""
--------CANONICAL SOLUTION--------
temp_a, temp_b = a, b
if isinstance(temp_a, str): temp_a = temp_a.replace(',','.')
if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')
if float(temp_a) == float(temp_b): return None
return a if float(temp_a) > float(temp_b) else b
---------------------------------------INFO ABOUT TEST 137 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 138----------------------------------------
-------------PROMPT----------------
def is_equal_to_sum_even(n):
"""Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
is_equal_to_sum_even(4) == False
is_equal_to_sum_even(6) == False
is_equal_to_sum_even(8) == True
"""
--------CANONICAL SOLUTION--------
return n%2 == 0 and n >= 8
---------------------------------------INFO ABOUT TEST 138 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 139----------------------------------------
-------------PROMPT----------------
def special_factorial(n):
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer.
"""
--------CANONICAL SOLUTION--------
fact_i = 1
special_fact = 1
for i in range(1, n+1):
fact_i *= i
special_fact *= fact_i
return special_fact
---------------------------------------INFO ABOUT TEST 139 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 140----------------------------------------
-------------PROMPT----------------
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2") == "_Example_2"
fix_spaces(" Example 3") == "_Example-3"
"""
--------CANONICAL SOLUTION--------
new_text = ""
i = 0
start, end = 0, 0
while i < len(text):
if text[i] == " ":
end += 1
else:
if end - start > 2:
new_text += "-"+text[i]
elif end - start > 0:
new_text += "_"*(end - start)+text[i]
else:
new_text += text[i]
start, end = i+1, i+1
i+=1
if end - start > 2:
new_text += "-"
elif end - start > 0:
new_text += "_"
return new_text
---------------------------------------INFO ABOUT TEST 140 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 141----------------------------------------
-------------PROMPT----------------
def file_name_check(file_name):
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
file_name_check("example.txt") # => 'Yes'
file_name_check("1example.dll") # => 'No' (the name should start with a latin alphapet letter)
"""
--------CANONICAL SOLUTION--------
suf = ['txt', 'exe', 'dll']
lst = file_name.split(sep='.')
if len(lst) != 2:
return 'No'
if not lst[1] in suf:
return 'No'
if len(lst[0]) == 0:
return 'No'
if not lst[0][0].isalpha():
return 'No'
t = len([x for x in lst[0] if x.isdigit()])
if t > 3:
return 'No'
return 'Yes'
---------------------------------------INFO ABOUT TEST 141 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 142----------------------------------------
-------------PROMPT----------------
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries.
Examples:
For lst = [1,2,3] the output should be 6
For lst = [] the output should be 0
For lst = [-1,-5,2,-1,-5] the output should be -126
"""
--------CANONICAL SOLUTION--------
result =[]
for i in range(len(lst)):
if i %3 == 0:
result.append(lst[i]**2)
elif i % 4 == 0 and i%3 != 0:
result.append(lst[i]**3)
else:
result.append(lst[i])
return sum(result)
---------------------------------------INFO ABOUT TEST 142 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 143----------------------------------------
-------------PROMPT----------------
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Input: sentence = "This is a test"
Output: "is"
Example 2:
Input: sentence = "lets go for swimming"
Output: "go for"
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
"""
--------CANONICAL SOLUTION--------
new_lst = []
for word in sentence.split():
flg = 0
if len(word) == 1:
flg = 1
for i in range(2, len(word)):
if len(word)%i == 0:
flg = 1
if flg == 0 or len(word) == 2:
new_lst.append(word)
return " ".join(new_lst)
---------------------------------------INFO ABOUT TEST 143 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 144----------------------------------------
-------------PROMPT----------------
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify("1/5", "5/1") = True
simplify("1/6", "2/1") = False
simplify("7/10", "10/2") = False
"""
--------CANONICAL SOLUTION--------
a, b = x.split("/")
c, d = n.split("/")
numerator = int(a) * int(c)
denom = int(b) * int(d)
if (numerator/denom == int(numerator/denom)):
return True
return False
---------------------------------------INFO ABOUT TEST 144 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 145----------------------------------------
-------------PROMPT----------------
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
>>> order_by_points([]) == []
"""
--------CANONICAL SOLUTION--------
def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return sorted(nums, key=digits_sum)
---------------------------------------INFO ABOUT TEST 145 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 146----------------------------------------
-------------PROMPT----------------
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter([33, -2, -3, 45, 21, 109]) => 2
"""
--------CANONICAL SOLUTION--------
count = 0
for num in nums:
if num > 10:
odd_digits = (1, 3, 5, 7, 9)
number_as_string = str(num)
if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:
count += 1
return count
---------------------------------------INFO ABOUT TEST 146 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 147----------------------------------------
-------------PROMPT----------------
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Input: n = 5
Output: 1
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
"""
--------CANONICAL SOLUTION--------
A = [i*i - i + 1 for i in range(1,n+1)]
ans = []
for i in range(n):
for j in range(i+1,n):
for k in range(j+1,n):
if (A[i]+A[j]+A[k])%3 == 0:
ans += [(A[i],A[j],A[k])]
return len(ans)
---------------------------------------INFO ABOUT TEST 147 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 148----------------------------------------
-------------PROMPT----------------
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a tuple containing all planets whose orbits are
located between the orbit of planet1 and the orbit of planet2, sorted by
the proximity to the sun.
The function should return an empty tuple if planet1 or planet2
are not correct planet names.
Examples
bf("Jupiter", "Neptune") ==> ("Saturn", "Uranus")
bf("Earth", "Mercury") ==> ("Venus")
bf("Mercury", "Uranus") ==> ("Venus", "Earth", "Mars", "Jupiter", "Saturn")
'''
--------CANONICAL SOLUTION--------
planet_names = ("Mercury", "Venus", "Earth", "Mars", "Jupiter", "Saturn", "Uranus", "Neptune")
if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:
return ()
planet1_index = planet_names.index(planet1)
planet2_index = planet_names.index(planet2)
if planet1_index < planet2_index:
return (planet_names[planet1_index + 1: planet2_index])
else:
return (planet_names[planet2_index + 1 : planet1_index])
---------------------------------------INFO ABOUT TEST 148 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 149----------------------------------------
-------------PROMPT----------------
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert list_sort(["aa", "a", "aaa"]) => ["aa"]
assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
"""
--------CANONICAL SOLUTION--------
lst.sort()
new_lst = []
for i in lst:
if len(i)%2 == 0:
new_lst.append(i)
return sorted(new_lst, key=len)
---------------------------------------INFO ABOUT TEST 149 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 150----------------------------------------
-------------PROMPT----------------
def x_or_y(n, x, y):
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5
"""
--------CANONICAL SOLUTION--------
if n == 1:
return y
for i in range(2, n):
if n % i == 0:
return y
break
else:
return x
---------------------------------------INFO ABOUT TEST 150 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 151----------------------------------------
-------------PROMPT----------------
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_difference([9, -2]) == 81
double_the_difference([0]) == 0
If the input list is empty, return 0.
'''
--------CANONICAL SOLUTION--------
return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
---------------------------------------INFO ABOUT TEST 151 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 152----------------------------------------
-------------PROMPT----------------
def compare(game,guess):
"""I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]
compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]
"""
--------CANONICAL SOLUTION--------
return [abs(x-y) for x,y in zip(game,guess)]
---------------------------------------INFO ABOUT TEST 152 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 153----------------------------------------
-------------PROMPT----------------
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the list.
For example, if you are given "Slices" as the class and a list of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'
"""
--------CANONICAL SOLUTION--------
strong = extensions[0]
my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])
for s in extensions:
val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])
if val > my_val:
strong = s
my_val = val
ans = class_name + "." + strong
return ans
---------------------------------------INFO ABOUT TEST 153 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 154----------------------------------------
-------------PROMPT----------------
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("abab","baa") => True
cycpattern_check("efef","eeff") => False
cycpattern_check("himenss","simen") => True
"""
--------CANONICAL SOLUTION--------
l = len(b)
pat = b + b
for i in range(len(a) - l + 1):
for j in range(l + 1):
if a[i:i+l] == pat[j:j+l]:
return True
return False
---------------------------------------INFO ABOUT TEST 154 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 155----------------------------------------
-------------PROMPT----------------
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
--------CANONICAL SOLUTION--------
even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
even_count +=1
else:
odd_count +=1
return (even_count, odd_count)
---------------------------------------INFO ABOUT TEST 155 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 156----------------------------------------
-------------PROMPT----------------
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxxvi'
"""
--------CANONICAL SOLUTION--------
num = [1, 4, 5, 9, 10, 40, 50, 90,
100, 400, 500, 900, 1000]
sym = ["I", "IV", "V", "IX", "X", "XL",
"L", "XC", "C", "CD", "D", "CM", "M"]
i = 12
res = ''
while number:
div = number // num[i]
number %= num[i]
while div:
res += sym[i]
div -= 1
i -= 1
return res.lower()
---------------------------------------INFO ABOUT TEST 156 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 157----------------------------------------
-------------PROMPT----------------
def right_angle_triangle(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return True if the three
sides form a right-angled triangle, False otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
right_angle_triangle(3, 4, 5) == True
right_angle_triangle(1, 2, 3) == False
'''
--------CANONICAL SOLUTION--------
return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
---------------------------------------INFO ABOUT TEST 157 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 158----------------------------------------
-------------PROMPT----------------
def find_max(words):
"""Write a function that accepts a list of strings.
The list contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
find_max(["name", "of", "string"]) == "string"
find_max(["name", "enam", "game"]) == "enam"
find_max(["aaaaaaa", "bb" ,"cc"]) == ""aaaaaaa"
"""
--------CANONICAL SOLUTION--------
return sorted(words, key = lambda x: (-len(set(x)), x))[0]
---------------------------------------INFO ABOUT TEST 158 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 159----------------------------------------
-------------PROMPT----------------
def eat(number, need, remaining):
"""
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
* eat(5, 6, 10) -> [11, 4]
* eat(4, 8, 9) -> [12, 1]
* eat(1, 10, 10) -> [11, 0]
* eat(2, 11, 5) -> [7, 0]
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
"""
--------CANONICAL SOLUTION--------
if(need <= remaining):
return [ number + need , remaining-need ]
else:
return [ number + remaining , 0]
---------------------------------------INFO ABOUT TEST 159 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 160----------------------------------------
-------------PROMPT----------------
def do_algebra(operator, operand):
"""
Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator list is equal to the length of operand list minus one.
Operand is a list of of non-negative integers.
Operator list has at least one operator, and operand list has at least two operands.
"""
--------CANONICAL SOLUTION--------
expression = str(operand[0])
for oprt, oprn in zip(operator, operand[1:]):
expression+= oprt + str(oprn)
return eval(expression)
---------------------------------------INFO ABOUT TEST 160 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 161----------------------------------------
-------------PROMPT----------------
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("ab") = "AB"
solve("#a@C") = "#A@c"
"""
--------CANONICAL SOLUTION--------
flg = 0
idx = 0
new_str = list(s)
for i in s:
if i.isalpha():
new_str[idx] = i.swapcase()
flg = 1
idx += 1
s = ""
for i in new_str:
s += i
if flg == 0:
return s[len(s)::-1]
return s
---------------------------------------INFO ABOUT TEST 161 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 162----------------------------------------
-------------PROMPT----------------
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
--------CANONICAL SOLUTION--------
import hashlib
return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
---------------------------------------INFO ABOUT TEST 162 DONE-------------------------------------------
---------------------------------------WRITING INFO ABOUT TEST 163----------------------------------------
-------------PROMPT----------------
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
--------CANONICAL SOLUTION--------
lower = max(2, min(a, b))
upper = min(8, max(a, b))
return [i for i in range(lower, upper+1) if i % 2 == 0]
---------------------------------------INFO ABOUT TEST 163 DONE-------------------------------------------
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