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Умножение на матрици via pointers
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#include <iostream> | |
using namespace std; | |
const int MAX = 100; | |
void printMatrix(int *m, int N) | |
{ | |
int i = 1; | |
for (int *ptr1 = m; ptr1 < m + N * N; ++ptr1, ++i) | |
{ | |
std::cout << *ptr1 << ' '; | |
if (i > 0 && i % N == 0) | |
{ | |
cout << '\n'; | |
} | |
} | |
} | |
int main() | |
{ | |
int N; | |
int buffer; | |
cout << "N="; | |
cin >> N; | |
int matrix1[MAX * MAX]; | |
int matrix2[MAX * MAX]; | |
int matrix3[MAX * MAX]; | |
int *ptr1, *ptr2, *ptr3; | |
// int ik, kj; | |
for (ptr1 = matrix1; ptr1 < matrix1 + N * N; ptr1++) | |
{ | |
cin >> *ptr1; | |
} | |
// printMatrix(matrix1, N); | |
for (ptr2 = matrix2; ptr2 < matrix2 + N * N; ptr2++) | |
{ | |
cin >> *ptr2; | |
} | |
// printMatrix(matrix2, N); | |
for (int i = 0; i < N; i++) | |
{ | |
for (int j = 0; j < N; j++) | |
{ | |
ptr3 = matrix3; | |
buffer = 0; | |
for (int k = 0; k < N; k++) | |
{ | |
ptr1 = matrix1 + ((i * N) + k); | |
ptr2 = matrix2 + ((k * N) + j); | |
// std::cout << "ptr1: " << *ptr1 << '\n'; | |
// std::cout << "ptr2: " << *ptr2 << '\n'; | |
buffer += (*(ptr1) * *(ptr2)); | |
} | |
*(ptr3 + ((i * N) + j)) = buffer; | |
} | |
} | |
printMatrix(matrix3, N); | |
return 0; | |
} |
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