Find numbers divisibles by 2, 3 y 5

findDivisor.js

function findDivisor() {

  var numbers = [];
  var number = 100000;

  while (numbers.length < 6) {
    for (var i = 0; i < 6; i++) {
      if (number % 2 == 0 && number % 3 == 0 && number % 5 == 0){
        var divisor = numbers.push(number);
      }
      number++;
    }
  }

  console.log(numbers);

}

findDivisor();