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Java program to check whether given number is Armstrong or not?
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package com.javamultiplex.number; | |
import java.util.Scanner; | |
public class ArmstrongNumber { | |
public static void main(String[] args) { | |
Scanner input = null; | |
try { | |
input = new Scanner(System.in); | |
System.out.println("Enter number : "); | |
String num = input.next(); | |
if (isValidNumber(num)) { | |
int length = num.length(); | |
int temp = 0, sum = 0; | |
for (int i = 0; i < length; i++) { | |
// Converting char to int. | |
temp = num.charAt(i) - 48; | |
sum += temp * temp * temp; | |
} | |
// Converting int to String. | |
String finalSum = String.valueOf(sum); | |
if (num.equals(finalSum)) { | |
System.out.println(num + " is an Armstrong number."); | |
} else { | |
System.out.println(num + " is not an Armstrong number."); | |
} | |
} else { | |
System.out.println("Please enter valid number."); | |
} | |
} finally { | |
if (input != null) { | |
input.close(); | |
} | |
} | |
} | |
private static boolean isValidNumber(String num) { | |
String pattern = "^[0-9]+$"; | |
boolean result = false; | |
if (num.matches(pattern)) { | |
result = true; | |
} | |
return result; | |
} | |
} |
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