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@javamultiplex
Created September 20, 2017 11:55
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Binary to Octal Converter
package com.javamultiplex.baseconversion;
import java.util.Scanner;
/**
*
* @author Rohit Agarwal
* @category Base Conversion
* @problem Convert Binary to Octal
*
*/
public class BinaryToOctal {
public static void main(String[] args) {
Scanner input = null;
try {
input = new Scanner(System.in);
System.out.println("Enter binary number : ");
String number = input.next();
if (isBinaryNumber(number)) {
String octal = getOctalFromBinaryNumber(number);
System.out.println("Octal Number : " + octal);
} else {
System.out.println("Please enter valid binary number.");
}
} finally {
if (input != null) {
input.close();
}
}
}
private static String getOctalFromBinaryNumber(String number) {
// Convert Binary to Decimal.
int decimal = getDecimalFromBinaryNumber(number);
// Convert Decimal to Octal.
String octal = getOctalFromDecimalNumber(decimal);
return octal;
}
private static String getOctalFromDecimalNumber(int decimal) {
int remainder = 0;
StringBuilder octal = new StringBuilder();
while (decimal != 0) {
remainder = decimal % 8;
// Converting Integer to String and adding into StringBuilder.
octal.append(String.valueOf(remainder));
decimal = decimal / 8;
}
// Reverse String using library function of StringBuilder class.
return octal.reverse().toString();
}
private static int getDecimalFromBinaryNumber(String number) {
// Converting String to StringBuilder.
StringBuilder string = new StringBuilder(number);
string = string.reverse();
int length = string.length();
int digit, power, sum = 0;
for (int i = 0; i < length; i++) {
digit = string.charAt(i) - 48;
power = (int) Math.pow(2, i);
sum = sum + digit * power;
}
return sum;
}
private static boolean isBinaryNumber(String number) {
/*
* Regular expression that matches string containing only binary
* digits[0-1].
*/
String pattern = "^[01]+$";
boolean result = false;
if (number.matches(pattern)) {
result = true;
}
return result;
}
}
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