Skip to content

Instantly share code, notes, and snippets.

@javamultiplex
Created September 25, 2017 13:25
Show Gist options
  • Save javamultiplex/b906b8a426e0b3ea612c1c8ede8f7c81 to your computer and use it in GitHub Desktop.
Save javamultiplex/b906b8a426e0b3ea612c1c8ede8f7c81 to your computer and use it in GitHub Desktop.
How to get file permissions in Java?
package com.javamultiplex.filehandling;
import java.io.File;
import java.io.IOException;
import java.util.Scanner;
/**
*
* @author Rohit Agarwal
* @category File Handling
* @problem How to get given file permissions in Java?
*
*/
public class FilePermission {
public static void main(String[] args) throws IOException {
Scanner input = null;
try {
input = new Scanner(System.in);
System.out.println("Enter file name with extension : ");
String fileName = input.nextLine();
if (isValidFileName(fileName)) {
// file present in current working directory.
File file = new File(fileName);
if (file.exists()) {
System.out.println("Executable : " + file.canExecute());
System.out.println("Readable : " + file.canRead());
System.out.println("Writable : " + file.canWrite());
} else {
System.out.println("File is not present in current directory.");
}
} else {
System.out.println("File name is not valid.");
}
} finally {
if (input != null) {
input.close();
}
}
}
private static boolean isValidFileName(String fileName) {
// Regular expression for validating file name.
String pattern = "^.+\\..+$";
boolean result = false;
if (fileName.matches(pattern)) {
result = true;
}
return result;
}
}
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment