Created
January 11, 2012 01:39
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FizzBuzz JavaScript solution
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for (var i=1; i <= 20; i++) | |
{ | |
if (i % 15 == 0) | |
console.log("FizzBuzz"); | |
else if (i % 3 == 0) | |
console.log("Fizz"); | |
else if (i % 5 == 0) | |
console.log("Buzz"); | |
else | |
console.log(i); | |
} |
for (let i = 1; i <= 100; i++) {
const fizz = i % 3 === 0 ? "Fizz" : ""
const buzz = i % 5 === 0 ? "Buzz" : ""
console.log(`${fizz}${buzz}` || i)
}
const fizzBuzz = (num, rules) => {
const result = [];
for (let i = 1; i <= num; i++) {
result.push(applyRules(i, rules));
}
return result;
};
const applyRules = (num, rules) => {
const output = rules.reduce((result, rule) => {
if (rule.condition(num)) {
result += rule.output;
}
return result;
}, '');
return output || num;
};
// Example usage:
const isMultipleOf = (n) => (num) => num % n === 0;
const rules = [
{ condition: isMultipleOf(3), output: 'Fizz' },
{ condition: isMultipleOf(5), output: 'Buzz' },
];
const resultArray = fizzBuzz(15, rules);
console.log(resultArray);
//para imprimir en la página web const n= window.prompt("Ingrese un número: "); for(i=1; i<=n; i++) if(i%3==0 && i%5==0){ console.log("FizzBuzz\n"); } else if(i%3==0 && i%5!=0){ console.log("Fizz\n"); } else if(i%3!=0 && i%5==0){ console.log("Buzz\n"); } else{ console.log(i\n); }
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Thanks man, was looking for switch case implementation on this one.