Standardizes duplicate id's with different equivalent names, aka aliases, to an easier object.

aliasinate.py

import itertools
from operator import itemgetter

def aliasinate(lst, sep=';') -> dict:
    '''
    Parameters
    ----------
    lst : list
        List of strings containing aliases in any order or combination. 
    
    Returns
    -------
    mapping : dict(set(str))
        Dictionary with keys being aliases with values being other keys. 

    Examples
    --------
        >>> aliasinate(['a;b;c','d', 'e;c','e'])
        {'A': {'A', 'B', 'C'},
         'B': {'A', 'B', 'C'},
         'C': {'A', 'B', 'C', 'E'},
         'D': {'D'},
         'E': {'C', 'E'}}
    '''
    mapper = []
    for i, row in enumerate(lst): 
        for alias in row.split(';'):
            mapper.append((alias.upper(), i))
    
    # group by row number 
    mapper = sorted(mapper, key=itemgetter(1))
    gb_row_num = {k:[j[0] for j in list(v)] \
                for k,v in itertools.groupby(mapper, key=itemgetter(1))}
    
    # group by alias; add aliases with same row num
    mapper = sorted(mapper, key=itemgetter(0))
    dmap = dict()
    for alias, group in itertools.groupby(mapper, key=itemgetter(0)):
        row_nums = [i[1] for i in list(group)]
        dmap[alias] = set(itertools.chain(*[list(gb_row_num[n]) for n in row_nums]))
    return dmap