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Last active December 14, 2022 05:03
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Employees with duplicate phone numbers that are cross-company
select
e.phone_number,
e.name,
e.public_id as employee_public_id,
c.name as company_name,
c.public_id as company_public_id,
d.name as division_name,
d.public_id as division_public_id
from customers_employee e
left join customers_company c on e.company_id = c.id
left join customers_division d on e.division_id = d.id
where
is_active=true and
phone_number in (
select
phone_number
from customers_employee
where
is_active=true and
phone_number is not null and
phone_number != ''
group by phone_number
having count(distinct(company_id)) > 1
)
group by
e.phone_number,
e.name,
e.public_id,
c.name,
c.public_id,
d.name,
d.public_id
order by 1;
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