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<?php | |
/* | |
* Problem: | |
* Given a set of intervals, print all NON overlapping intervals | |
* after merging overlapping intervals. | |
* | |
* Assumptions: | |
* 1. The start of the interval is less than or equal to the end | |
* 2. The input is sorted by the start of the interval in asc order | |
* 3. The intervals are made u of positive integers | |
*/ | |
// The sample input from the problem | |
$input = [ | |
[1, 5], | |
[2, 3], | |
[4, 6], | |
[7, 8], | |
[8, 10], | |
[12, 15], | |
]; | |
/* | |
* Expected output: | |
* $input = [ | |
* [1, 6], | |
* [7, 10], | |
* [12, 15], | |
* ]; | |
*/ | |
// Sort by the start of the interval | |
usort($input, function ($a, $b) { | |
return $a[0] - $b[0]; | |
}); | |
$output = []; | |
// While we still have unchecked intervals | |
while (count($input)) { | |
// Get and remove the first interval from the input | |
$current = array_shift($input); | |
// Iterate through the the remaining ordered intervals | |
// and merge overlapping intervals until | |
// we exceed the upper bounds of the current merged interval | |
foreach ($input as $index => $interval) { | |
// Break if no overlap is possible | |
if ($current[1] < $interval[0]) { | |
break; | |
} | |
// Must have overlap based on sorting so | |
// increase the end of the current if necessary | |
$current[1] = $current[1] > $interval[1] | |
? $current[1] | |
: $interval[1]; | |
// Remove merged interval from the input | |
unset($input[$index]); | |
} | |
// Add fully merged interval to output list | |
$output[] = $current; | |
} | |
print_r($output); |
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