Jesus Sanchez jgsanchezg

## perfectsquare.js
/*
1. Initialize left=1 & Right=n
2. Calculate mid = Math.floor((left + right) / 2);
2. If mid*mid = n, then n is Perfect Square
3. Else if mid*mid > n then right = mid - 1
4. Else if mid*mid < n then left = mid + 1
*/


const perfectSquare = (number) => {
	/*
	1. Initialize left=1 & Right=n
	2. Calculate mid = Math.floor((left + right) / 2);
	2. If mid*mid = n, then n is Perfect Square
	3. Else if mid*mid > n then right = mid - 1
	4. Else if mid*mid < n then left = mid + 1
	*/


	const perfectSquare = (number) => {