Created
December 8, 2017 07:32
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Given a node in binary search tree, find the successor in ascending order traversal.
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using System; | |
class Solution | |
{ | |
public class Node | |
{ | |
public int value; | |
public Node left {get; set;} | |
public Node right {get; set;} | |
public Node parent {get; set;} | |
public Node(int val) | |
{ | |
value = val; | |
} | |
} | |
public static Node findInOrderSuccessor(Node inputNode) // give 9, find 11; give 14, find 20 | |
{ | |
if(inputNode == null) // false , false | |
{ | |
return null; | |
} | |
var hasRightChild = inputNode.right != null; // true, false | |
if(hasRightChild) | |
{ | |
// find minimum of right subtree | |
var minimumNode = inputNode.right; // node 12 | |
while(minimumNode != null && minimumNode.left != null) // node 11 | |
{ | |
minimumNode = minimumNode.left; // node 11 | |
} | |
return minimumNode; // return node 11 | |
} | |
else | |
{ | |
// check parent node | |
var value = inputNode.value; // 14 | |
var current = inputNode; // node 14 | |
while(current != null || current.parent != null) // node 12 != null ; node20!= null | |
{ | |
if(current.parent.value > value) // 12 > 14, false , 9 > 14 false ; 20 > 14 | |
{ | |
return current.parent; // node 20 | |
} | |
current = current.parent; // current = node 12, current = 9 | |
} | |
return null; | |
} | |
} | |
static void Main(string[] args) | |
{ | |
// test findInOrderSuccessor here | |
var node20 = new Node(20); | |
node20.left = new Node(9); | |
node20.right = new Node(25); | |
node20.left.parent = node20; | |
node20.right.parent = node20; | |
var node9 = node20.left; | |
node9.right = new Node(12); | |
var node12 = node9.right; | |
node12.parent = node9; | |
node12.left = new Node(11); | |
node12.right = new Node(14); | |
var node11 = node12.left; | |
var node14 = node12.right; | |
node11.parent = node12; | |
node14.parent = node12; | |
var node11Success = findInOrderSuccessor(node11); | |
Console.WriteLine(node11Success.value); | |
var node14Success = findInOrderSuccessor(node14); | |
Console.WriteLine(node14Success.value); | |
} | |
} | |
/* | |
3 | |
root = Node(20) | |
root.left = Node(9) | |
root.rig | |
Give value 9 - find right substree minimum node | |
12 | |
11 14 | |
smallest number 11 BST successor | |
Give value 11, no right child | |
parent node -> 12 > 11, 12 may be the successor, go | |
Give value 14, no right child -> parent -> 12 < 14 -> it is not possible | |
-> 9 < 14 (no) -> 20 -> 20 > 14 -> 20 is the successor | |
Give 25, -> 20 < 25 -> return null | |
*/ |
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